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Natasha_Volkova [10]
3 years ago
9

How do i figure out this problem? Order from least to greatest. 1.54,2.53,1.504,1.9?

Mathematics
2 answers:
Sphinxa [80]3 years ago
8 0
1.504 1.54 1.9 2.53 ..
Anna [14]3 years ago
7 0
Look at the first number
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(48. PERSEVERE Wha
katrin2010 [14]

Answer: 4

Step-by-step explanation:

We know that a plane is 2 dimensional surface that extends infinitely far.

The number of points required to define a plane = 3

Here , we have 4 points A, B, C, and D.

So, the number of possible combinations of 3 points to make a plane from 4 points = C(4,3)

=4            [ C(n,n-1)=n ]

Hence, the greatest number of planes determined using any three of the points A, B, C, and D if no three points are collinear = 4.

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3 years ago
Describe a sequence of transformations that maps triangle ABC onto triangle A"B"C"<br> Help please?
monitta

the answer is reflection

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How does this graph change between point D and point G?
Leona [35]

Answer:

i don't see the graph

Step-by-step explanation:

3 0
3 years ago
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154 and 145 to the nearest hundred
Yuki888 [10]

Answer: 154: 200 145: 100

Step-by-step explanation:

If the number next to the place value is 5 or more you round it up. Like I did 154. But if the number is less that 5 you put everything to zero EXCEPT for the place value you are rounding. Good Luck

5 0
2 years ago
Read 2 more answers
It is possible to get 2 solutions when the system of equations is: (check all that apply)
SVETLANKA909090 [29]

Answer:

A system of the equation of a circle and a linear equation

A system of the equation of a parabola and a linear equation

Step-by-step explanation:

Let us verify our answer

A system of the equation of a circle and a linear equation

Let an equation of a circle as x^2+ y^2 = 1 ..........(1)

Let a liner equation Y = x ............(2)

substitute (2) in (1)

x^2 + x^2 = 1\\2x^2 = 1\\

x^2 = \frac{1}{\sqrt{2} } \\x = +\frac{1}{\sqrt{2} } , -\frac{1}{\sqrt{2} }  so Y = +\frac{1}{\sqrt{2} } , -\frac{1}{\sqrt{2} }

so the two solution are ( (\frac{1}{\sqrt{2} } ,\frac{1}{\sqrt{2} }) (-\frac{1}{\sqrt{2} }, -\frac{1}{\sqrt{2} })

A system of the equation of a parabola and a linear equation

Let equation of Parabola be y^2 = x

and linear equation y = x

substitute

x^2 = x\\x^2 - x= 0\\x(x-1) = \\x = 0 , 1

Y = 0,1

so the two solutions will be (0,0) and (1,1)

3 0
2 years ago
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