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PtichkaEL [24]
4 years ago
13

the number of girls is eight less than twice the number of boys in the ohs 10th grade class of three are a total of 121 tenth gr

aders at ohs how many of them are boys and how many of them are girls
Mathematics
1 answer:
Oksi-84 [34.3K]4 years ago
7 0
Eight less than. I hope this helped. Keep up the good work
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What is the cost of 5 pounds of peppers if 4 pounds cost $2.60
sergeinik [125]

2.60

\frac{2.60}{4} =  \frac{13}{20} \times 5 = 3.25

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5 0
4 years ago
3. A boy mixed 500g of sugar and 120g of salt in 106g of lime juice. What will be the
Fed [463]

Answer:

Option C...726 g

Step-by-step explanation:

Mass of;

sugar = 500g

salt = 120g

lime juice = 106g

mass of mixture = sum of its components

= 500g + 120g + 106g

=726 g

6 0
3 years ago
Please help <br> What is the slope of a line that is parallel to the line shown?
9966 [12]
4/6 and (0,1) is the answers
4 0
4 years ago
Read 2 more answers
The graph of y= e^x is transformed as showed in the graph below. Which equation represents the transformed equation
Goryan [66]

The parent function y=e^x passes through the point (0,1), since e^0=1

Your function passes through the point (0,4), which means that the parent function has been translated 3 units up.

To translate a function vertically, you have to add a constant, i.e. you have to transform f(x)\mapsto f(x)+k

k is the amount of units you want to translate: positive if you translate upwards, negative if you translate downwards.

In your case, you move 3 units upwards, so you want k=3 and your function is

y=e^x+3

5 0
3 years ago
Find the perimeter of quadrilateral PQRS with the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3).
storchak [24]

Answer:

P=16.53\ units

Step-by-step explanation:

we know that

The perimeter of quadrilateral PQRS is equal to the sum of its four length sides

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3)

step 1

Find the distance PQ

P(2,4), Q(2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(2-2)^{2}}

d=\sqrt{(-1)^{2}+(0)^{2}}

d=\sqrt{1}

dPQ=1\ unit

step 2

Find the distance QR

Q(2,3), R(-2,-2)

substitute in the formula

d=\sqrt{(-2-3)^{2}+(-2-2)^{2}}

d=\sqrt{(-5)^{2}+(-4)^{2}}

dQR=\sqrt{41}\ units

step 3

Find the distance RS

R(-2,-2), and S(-2,3)

substitute in the formula

d=\sqrt{(3+2)^{2}+(-2+2)^{2}}

d=\sqrt{(5)^{2}+(0)^{2}}

dRS=5\ units

step 4

Find the distance PS

P(2,4), S(-2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(-2-2)^{2}}

d=\sqrt{(-1)^{2}+(-4)^{2}}

dPS=\sqrt{17}\ units

step 5

Find the perimeter

P=PQ+QR+RS+PS

substitute the values

P=1+\sqrt{41}+5+\sqrt{17}

P=6+\sqrt{41}+\sqrt{17}

P=16.53\ units

5 0
3 years ago
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