Answer:
markers are 29.76 m far apart in the laboratory
Explanation:
Given the data in the question;
speed of particle = 0.624c
lifetime = 159 ns = 1.59 × 10⁻⁷ s
we know that; c is speed of light which is equal to 3 × 10⁸ m/s
we know that
distance = vt
or s = ut
so we substitute
distance = 0.624c × 1.59 × 10⁻⁷ s
distance = 0.624(3 × 10⁸ m/s) × 1.59 × 10⁻⁷ s
distance = 1.872 × 10⁸ m/s × 1.59 × 10⁻⁷ s
distance = 29.76 m
Therefore, markers are 29.76 m far apart in the laboratory
D. Unbalanced forces are acting on it.
hope this helped
Answer:
(B) 1.23 x 10⁴ J
Explanation:
Given;
radius of the sphere, r = 7.0 m
diameter of the sphere, d = 2r = 14.0 m
mass of the person sitting on the sphere, m = 90.0 kg
The gravitational potential energy of the person is given by;
P.E = mgh
where;
g is acceleration due to gravity = 9.8 m/s²
h is the height above the ground level = d = 14.0 m
P.E = mgh
P.E = (90)(9.8)(14)
P.E = 12348 J
P.E = 1.2348 x 10⁴ J
Therefore, the gravitational potential energy of the person is 1.2348 x 10⁴ J
on a given inclined we know that net force is given by

here we know that

so here we have


so here acceleration depends directly on angle of inclination
now we also know that if height of the inclined is H and its length is L
then we can write

so the acceleration is given as

so acceleration also depends directly on height of the inclined plane
Given that
Work = 600,000 J ,
distance(S) = 500 m ,
mass (m) = 250 Kg ,
Determine the velocity of car (v) = ?
We know that,
Work = Force × distance
=> Force = Work ÷ distance
= 600,000 ÷ 500
= 500 N .
Also Force F = m.a ; from Newtons II law
500 = 250 × a
a = 2 m/s.
<em>Final Velocity from the given formula </em>
V² = u² + 2.a.s
= 0 + 2 × 2 × 500
= \sqrt{2000}
<em> v = 44.7 m/s</em>