Answer:
6m
Explanation:
The initial potential energy of the block P.E =mgh
where mass m = 3kg
g= 9.81 m/s2
h = 2m
Hence P.E = 3*9.81*2 = 58.8 Joules
This energy converts to kinetic energy when the block is released from the top
K.E = 
Solving for v, we obtain 6.26 m/s
The acceleration of the block by Newton's second law of motion,
ma = (μk)*mg
where μk = 0.1
Hence, a = 0.1*9.81 = 0.98m/s/s
Applying Newton's second equation of motion to solve,
where u = 0 m/s (released from rest0
Hence, 
Solving for s,
s= 20m
Therefore, the distance after two complete cycles = 20 -2(7) = 6m
Answer:
If he's 500 kg and 1 kg = 10 N then it would be 5,000 N
Explanation:
The surface area is unimportant and they'll use it to trick you.
Linear motion (also called rectilinear motion) is a motion along a straight line, and can therefore be described mathematically using only one spatial dimension.
Answer:
The maximum number of days for the trip
Explanation:
Given
--- Missing Equation
Required
What does d represent?
From the question, we understand that t represent the number of days;
So, by default 212 represent days
Going further:
For the equation, to be valid; the value of t must be within the interval;
When 
that is the beginning of the journey
As t increases;
212 - t decreases
Until the point where t = 212,
This signifies the end of the journey
So: 212 - t indicates a particular day between 0 and 212.
Hence, 212 represents the maximum number of days for the trip.
Answer:
the Jack speed is greater than the Nas speed
v₁ = 2.08 m / s > v2 = 1.85 m / s
Explanation:
For this exercise we can find the average speed of each of the boys, the average speed is defined as the displacement in the time interval
v = x / t
Jack.
It tells us that it travels x = 15 km in a time of t = 2 h
let's reduce the magnitudes to the SI system
x = 15 km (1000 m / 1 km) = 15 10³ m
t = 2 h (3600 s / 1 h) = 7200 s
let's calculate
v₁ = 15 10³/7200
v₁ = 2.08 m / s
Nas travels a distance of x = 10 km in a time of t = 1.5 h
x = 10 km = 10 10³ m
t = 1.5 h (3600s / 1h) = 5400 s
let's calculate the speed
v2 = 10 10³/5400
v2 = 1.85 m / s
From these results we can see that the Jack speed is greater than the Nas speed
