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murzikaleks [220]

3 years ago

14

100 POINTS Coronavirus cases rose from 23 cases on October 3rd to 103 cases on November 3rd .What was the percent increase based

on the original number of cases in October ? Please show work

1 answer:

evablogger [386]3 years ago

8 0

Answer:

<h2><em>348% increase</em></h2>

Step-by-step explanation:

103 - 23 / 23 = 3.47826

3.48 x 100% = 348%

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Lorena received a $50 gift card to an online store she wants to purchase some bracelets that cost $8 each there will be a $10 ov

Setler79 [48]

Minus the 10 from the 50, which makes 40. then divide 40 by 8
50-10=40
40÷8=5
n=5

3 0

3 years ago

A recipe calls for 3 cups of milk to make 30 biscuits. How many cups of milk will you need to make 45 biscuits?

anastassius [24]

The answer is: 4.5 cups.

The explanation is shown below:

1. You need 3 cups of milk to make 30 biscuits.

2. Therefore, to solve the exercise you only need to multiply 45 biscuits by 3 cups and divide this by 30 biscuits.

3. Let's call the cups you will need to make 45 biscuits $x$ . Then, you have:

$x=\frac{(45)(3)}{30}\\x=4.5$

4. Therefore, you will need 4.5 cups to make 45 biscuits.

4 0

3 years ago

33 1/3% of 360 please help I don’t understand

Mars2501 [29]

Answer:

33 1/3% of 360 is 120

Step-by-step explanation:

33 1/3 can be converted to 33.333% or simply just 1/3, divide 360 by 3 to get your answer which is 120.

3 0

3 years ago

Read 2 more answers

What is 10+5x60 .<br><br> A) 10<br> B)130<br> C)6767<br> D)4545454545

Lynna [10]

Answer:

310

but it doesnt show as a possible answer from your list

Step-by-step explanation:

5x60 is 300

then add 10 to 300

you get 310

7 0

3 years ago

Read 2 more answers

Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!

il63 [147K]

Answer:

$x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

Step-by-step explanation:

$w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

6 0

3 years ago