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Dafna1 [17]
3 years ago
10

What is the mass of a car that weighs 19,000 N on earth?

Physics
1 answer:
Anna71 [15]3 years ago
8 0
Divide by 9.8 I think
 so <span>1938.77551</span>
You might be interested in
What is the average power output pf a weight lifter who can lift 250 kg 2.0 m in 2.0 s
liq [111]

Answer:

Power = 2.45Kw or 2450 Watts.

Explanation:

<u>Given the following data;</u>

Mass, m = 250kg

Height, h = 2m

Time, t = 2secs

We know that acceleration due to gravity, g is equal to 9.8m/s²

Power can be defined as the energy required to do work per unit time.

Mathematically, it is given by the formula;

Power = \frac {Energy}{time}

But Energy = mgh

Substituting into the equation, we have

Power = \frac {mgh}{time}

Power = \frac {250*9.8*2}{2}

Power = \frac {4900}{2}

Power = 2450 Watts

To convert to kilowatt (Kw), we would divide by 1000

Power = 2450/1000

Power = 2.45Kw.

Therefore, the average power output of the weightlifter is 2.45 Kilowatts.

8 0
3 years ago
Which describes the movement of a fluid during convection?
VikaD [51]
The movement of a fluid during convection is a circular/oval motion since the fluid at the top sinks and the fluid at the bottom rises.

Hope this helps :)
3 0
3 years ago
A basketball player drops a 0.4-kg basketball vertically so that it is traveling at 5.7 m/s when it reaches the floor. The ball
Alik [6]

Answer:

(a) p = 3.4 kg-m/s (b) 37.78 N.

Explanation:

Mass of a basketball, m = 0.4 kg

Initial velocity of the ball, u = -5.7 m/s (as it comes down so it is negative)

It rebounds upward at a speed of 2.8 m/s  (as it rebounds so positive)

(a) Change in momentum = final momentum - initial momentum

p = m(v-u)

p = 0.4 (2.8-(-5.7))

p = 3.4 kg-m/s

(b) Impulse = change in momentum

Ft = 3.4

We have, t = 0.09 s

F=\dfrac{3.4}{0.09}\\\\F=37.78\ N

Hence, this is the required solution.

4 0
3 years ago
At what point does the external energy enter the system?
Phoenix [80]
The correct answer as the first one above !
8 0
3 years ago
What is the power of a machine that pushes with a force of 3 n for a distance of 9 m in 8 s?
dalvyx [7]
The work done by the machine is equal to the product between the force applied and the distance over which the force is applieds, so in this case:
W=Fd=(3 N)(9 m)=27 J

And the power of the machine is equal to the ratio between the work done by the machine and the time taken:
P= \frac{W}{t}= \frac{27 J}{8 s}=3.38 W

4 0
2 years ago
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