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3 years ago

What is the mass of a car that weighs 19,000 N on earth?

Physics

1 answer:

Anna71 [15]3 years ago

8 0

Divide by 9.8 I think
so <span>1938.77551</span>

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A car, initially traveling 28.0ft/s, steadily speeds up to 50.0ft/s in 7.40s. Determine all unknowns and answer the following qu

nataly862011 [7]

Explanation:

Given:

$v_0 = 28.0\:\text{ft/s}$

$v = 50.0\:\text{ft/s}$

$t = 7.40\:\text{s}$

First, we calculate the acceleration of the car during this time:

$v = v_0 + at \Rightarrow a = \dfrac{v - v_0}{t}$

Plugging in the given values, we get

$a = \dfrac{50.0\:\text{ft/s} - 28.0\:\text{ft/s}}{7.40\:\text{s}} = 2.97\:\text{ft/s}^2$

Now that we have the value for the acceleration, we can solve for the distance traveled during the time t:

$x = v_0t + \frac{1}{2}at^2$

$\:\:\:\:=(28.0\:\text{ft/s})(7.40\:\text{s})$

$\:\:\:\:\:\:\:\:\:\:\:\:+ \frac{1}{2}(2.97\:\text{ft/s}^2)(7.40\:\text{s})^2$

$\:\:\:\:= 289\:\text{ft}$

7 0

3 years ago

How much work is done by the force that moves the charge?

mina [271]

Answer:

The work done by the force is 6μJ

Explanation:

Suppose, A 30 nC charge is moved from a point where V₁ = 130 V to a point where V₂ = -70 V.

We need to calculate the work done by the force

Using formula of work done

$W=-q\Delta V$

Where, q = charge

$\Delta V$ =potential difference

Put the value into the formula

$W=-30\times10^{-9}\times(-70-130)$

$W=0.000006\ J$

$W=6\times10^{-6}\ J$

$W=6\ \mu J$

Hence, The work done by the force is 6μJ.

6 0

4 years ago

With its wheels locked, a van slides down a hill inclined at 40.0° to the horizonta l. Find the acceleration of this van A) if t

andreyandreev [35.5K]

Answer:

Explanation:

Check attachment for solution

7 0

4 years ago

What happens when electromagnetic waves cause a disturbance in electric

Leviafan [203]

Answer:

Explanation:

just answered it

7 0

3 years ago

Meteor Infrasound A meteor that explodes in the atmosphere creates infrasound waves that can travel multiple times around the gl

kherson [118]

Answer:

0.04455 Hz

Explanation:

Parameters given:

Wavelength, λ = 6.5km = 6500m

Distance travelled by the wave, x = 8830km = 8830000m

Time taken, t = 8.47hours = 8.47 * 3600 = 30492 secs

First, we find the speed of the wave:

Speed, v = distance/time = x/t

v = 8830000/30492 = 289.58 m/s

Frequency, f, is given as velocity divided by wavelength:

f = v/λ

f = 289.58/6500

f = 0.04455 Hz

8 0

3 years ago