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3 years ago

What is the mass of a car that weighs 19,000 N on earth?

Physics

1 answer:

Anna71 [15]3 years ago

8 0

Divide by 9.8 I think
so <span>1938.77551</span>

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3 years ago

Assume that in 2010 the United States will need 2.0×1012 watts of electric power produced by thousands of 1000 MW power plants.

Alex73 [517]

Answer:

1752.14 tonnes per year.

Explanation:

To solve this exercise it is necessary to apply the concepts related to power consumption and power production.

By conservation of energy we know that:

$\dot{P} = \bar{P}$

Where,

$\dot{P} =$ Production of Power

$\bar{P} =$ Consumption of power

Where the production of power would be,

$\dot{P} = m \dot{E}\eta$

Where,

m = Total mass required

$\dot{E} =$ Energy per Kilogram

$\eta =$ Efficiency

The problem gives us the aforementioned values under a production efficiency of 45%, that is,

$\dot{P} = \bar{P}$

$m \dot{E}\eta = \bar{P}$

Replacing the values we have,

$m(8*10^13)(0.45) = 2*10^{12}$

Solving for m,

$m = \frac{ 2*10^{12}}{(8*10^13)(0.45)}$

$m = 0.0556 \frac{kg}{s}$

We have the mass in kilograms and the time in seconds, we need to transform this to tons per year, then,

$m = 0.556\frac{kg}{s}*(\frac{3.1536*10^7s}{1year})(\frac{1ton}{1000kg})$

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8 0

3 years ago

A horse does 910 J of work in 380 seconds while pulling a wagon. What is the power output of the horse? Round your answer to two

frutty [35]

Answer: 2.4 watts

Explanation:

Work done by horse = 910J

Time = 380 seconds

Power output of the horse = ?

Recall that power is the rate of doing work. Thus, power is workdone divided by time taken.

i.e Power = (work/time)

Power = 910J/380seconds

Power = 2.395 watts (rounded to two significant figures as 2.4 watts)

Thus, the power output of the horse is 2.4 watts

7 0

3 years ago