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4 years ago

What landform is created when magma squeezes between rock layers to form a hardened slab of rock?

1 answer:

5 0

D. sill

A sill forms when hot magma squeezes between layers of rock to form a hardened sheet of rock. A sill is basically a tabular sheet intrusion between old layers of sedimentary rock, volcanic beds, or in the direction of foliation inherent in metamorphic rock. The word sill means a concordant intrusive sheet.

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Substance A has a higher heat capacity than does substance B, and substance B has a higher heat capacity than does substance C.

svetlana [45]

A < B < C

C will increase faster than B which is faster than A

5 0

3 years ago

A satellite at a particular point along an elliptical orbit has a gravitational potential energy of 5100 MJ with respect to Eart

serious [3.7K]

To solve this problem we will apply the theorem given in the conservation of energy, by which we have that it is conserved and that in terms of potential and kinetic energy, in their initial moment they must be equal to the final potential and kinetic energy. This is,

$E_{initial} = E_{final}$

$PE_{initial}+KE_{initial} = PE_{final}+KE_{final}$

Replacing the 5100MJ for satellite as initial potential energy, 4200MJ for initial kinetic energy and 5700MJ for final potential energy we have that

$KE_{final} = (PE_{initial}+KE_{initial} )-PE_{final}$

$KE_{final} = (5100+4200)-5700$

$KE_{final} = 3600MJ$

Therefore the final kinetic energy is 3600MJ

5 0

4 years ago

How long will a plane have to fly continuously with 900 miles per hour in order to cover the same distance as that from Earth to

hammer [34]

I'm not sure about the distance to the nearest star, but it's probably about 4 light-years (L-y).

1 L-y = 1.86 * 10E5 mi/sec * 3600 sec/hr * 24 hr/day * 365 day/yr

1 L-y = 5.9 *10E12 mi and 4 L-y = 2.3 *10E13 mi distance to star

2.3 * 10E13 mi / 900 mi/hr = 2.6 * 10E10 hr hours to star

2.6 * 10E10 hr / (24 hr/day) = 1.1 * 10E9 day days to star

1.1 * 10E9 day / 365 day/yr = 3 * 10E6 yr = 3 million years to star

4 0

3 years ago

A softball of mass 0.220 kg that is moving with a speed of 5.5 m/s (in the positive direction) collides head-on and elastically

Elanso [62]

Answer:

The velocity and mass of the target ball are 1.6 m/s and 1.29 kg.

Explanation:

Given that,

Mass of softball = 0.220 kg

Speed = 5.5 m/s

(a). We need to calculate the velocity of the target ball

Using conservation of momentum

$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}$

$0.220\times5.5+m_{2}\times0=0.220\times(-3.9)+m_{2}v_{2}$

$1.21=-0.858+m_{2}v_{2}$

$m_{2}v_{2}=2.068$ ....(I)

The velocity approach is equal to the separation of velocity

$u_{1}-u_{2}=v_{2}-v_{1}$

$5.5-0=v_{2}-(-3.9)$

$v_{2}=1.6\ m/s$

(b). We need to calculate the mass of the target ball

Now, Put the value of v₂ in equation (I)

$m_{2}\times1.6=2.068$

$m_{2}=\dfrac{2.068}{1.6}$

$m_{2}=1.29\ kg$

Hence, The velocity and mass of the target ball are 1.6 m/s and 1.29 kg.

3 0

3 years ago

Think back to coulomb's law. two coins with identical charges are placed on a lab table 1.35 m apart.

ziro4ka [17]

The Coulomb’s law is expressed mathematically as:

F = k * q1 * q2 / d^2

Where,

F = force of attraction between 2 particles = 2.0 N

k = Coulomb’s constant = 8.988 * 10^9 N m^2 / C^2

q = charge of the particle

d = distance between the 2 particles = 1.35 m

Since the two coins have identical charges therefore q1 = q2 =q

F = k* q^2 / d^2

2.0 N = (8.988 * 10^9 N m^2 / C^2) * q^2 / (1.35 m)^2

q = 2.01 * 10^-5 C

Therefore each coins have charges equivalent to 2.01 * 10^-5 C.

4 0

4 years ago