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iren [92.7K]
3 years ago
7

Causes damage to the alveoli and increases the production of mucus in the mouth, throat, and lungs.

Physics
2 answers:
Hatshy [7]3 years ago
4 0
I believe the answer is tar.
lord [1]3 years ago
4 0

Answer:

The correct answer is Tar.

Explanation:

Tar is the most toxic substance in tobacco smoke and is responsible for most of the diseases caused by smoking. This substance present in tobacco produces an irritating action on the respiratory tract.

This irritation leads to an increased production of

and a difficulty in eliminating it.

The secretion obstructs the airways, making it difficult for air to pass through. This results in chronic obstruction of the lung with rupture of the pulmonary alveoli.

Have a nice day!

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The instantaneous velocity of the object is its speed and direction at that instant.
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A 2-m long string is stretched between two supports with a tension that produces a wave speed equal to vw=50.00m/s. What are the
svetoff [14.1K]

Answer

given,

Length of the string, L = 2 m

speed of the wave , v = 50 m/s

string is stretched between two string

For the waves the nodes must be between the strings

the wavelength  is given by

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where n is the number of antinodes; n = 1,2,3,...

the frequency expression is given by

            f = n\dfrac{v}{2L}

now, wavelength calculation

      n = 1

           \lambda_1 = \dfrac{2\times 2}{1}

                    λ₁ = 4 m

      n = 2

           \lambda_2 = \dfrac{2\times 2}{2}

                   λ₂ = 2 m

      n =3

           \lambda_3 = \dfrac{2\times 2}{3}

                    λ₃ = 1.333 m

now, frequency calculation

      n = 1

            f = n\dfrac{v}{2L}

            f_1 =1\times \dfrac{50}{2\times 2}

                    f₁ = 12.5 Hz

      n = 2

            f = n\dfrac{v}{2L}

            f_2 =2\times \dfrac{50}{2\times 2}

                    f₂= 25 Hz

      n = 3

            f = n\dfrac{v}{2L}

            f_3 =3\times \dfrac{50}{2\times 2}

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8 0
3 years ago
How much equal charge should be placed on the earth and the moon so that the electrical repulsion balances the gravitational for
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As we know that electrostatic force between two charges is given as

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F_g = 1.98 \times 10^{20} N

here we can assume that both will have equal charge of magnitude "q"

now we have

1.98 \times 10^{20} = \frac{kq^2}{r^2}

1.98 \times 10^{20} = \frac{(9\times 10^9)(q^2)}{(3.84 \times 10^8)^2}

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Answer:

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