<span>D) Electromagnetic radiation travels in the form of longitudinal waves.</span>
The answer is C. An occluded front.
Answer:
6.8 m/s2
Explanation:
Let g = 9.8 m/s2. The total weight of both the rope and the mouse-robot is
W = Mg + mg = 1*9.8 + 2*9.8 = 29.4 N
For the rope to fails, the robot must act a force on the rope with an additional magnitude of 43 - 29.4 = 13.6 N. This force is generated by the robot itself when it's pulling itself up at an acceleration of
a = F/m = 13.6 / 2 = 6.8 m/s2
So the minimum magnitude of the acceleration would be 6.8 m/s2 for the rope to fail
Let the time be t.
so,In time t , distance travelled by 1st cyclist = 12.6 t
distance travelled by 2nd cyclist = 9.2t + 0.5 (1.5) t^2
Now, cyclist 1st is already 11.4 m ahead of 2nd cyclist.
so, 9.2t + 0.5 (1.5) t^2 = 11.4 + 12.6t
find t :
t = 6.77 sec
We add the values on each of the riders:
300 + 20 + 8
= 328 grams