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alekssr [168]
3 years ago
15

What is the speed of gravity

Physics
1 answer:
mojhsa [17]3 years ago
8 0
9.8m per seccond is the speed of gravity if you drop something like a ball from a tower
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How does the frequency of infrared electromagnetic waves compare with the frequency of radio and microwaves?
iVinArrow [24]

Answer:

Answer is B.

Because the wavelength of infrared is shorter than microwave radiation

8 0
3 years ago
Is this a testable question?
faltersainse [42]
This is a non testable question because it cannot be answered by doing an experiment. But it could be modified for example Dogs are more obedient then cats.
8 0
3 years ago
Read 2 more answers
Read the following and identify the main parts of the experiment.
slava [35]

The independent variable refers to the type of socks (synthetic socks), the dependent variable is the number of blisters and the control is the two weeks that she switches back to the cotton socks.

<h3>What is the dependent variable?</h3>

In an experiment, the dependent variable is those being tested and changes according to the independent variable.

The control group is the set of experimental conditions that is used to compare a given outcome in an experiment.

In conclusion, The independent variable refers to the type of socks (synthetic socks), the dependent variable is the number of blisters and the control is the two weeks that she switches back to the cotton socks.

Learn more about the dependent variable here:

brainly.com/question/25223322

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4 0
2 years ago
When a wire moves through a magnetic field, an electric current is produced in the wire. Why does this phenomenon occur?
Alenkasestr [34]

Answer:

<h2>It occurs whenever a magnetic field and an electric conductor move relative to one another so the conductor crosses lines of force in the magnetic field. </h2>

Explanation:

<h3>The current produced by electromagnetic induction is greater when the magnet or coil moves faster, the coil has more turns, or the magnet is stronger.</h3>

<h2>Carryonlearning </h2>
4 0
2 years ago
An extremely long wire laying parallel to the x -axis and passing through the origin carries a current of 250A running in the po
viktelen [127]

Answer:

1.232\times 10^{-5}\ T.

Explanation:

<u>Given:</u>

  • Current through the wire, passing through the origin, I_1 = 250\ A.
  • Current through the wire, passing through the y axis, r_y=1.8\ m., I_2 = 50\ A.

According to Ampere's circuital law, the line integral of magnetic field over a closed loop, called Amperian loop, is equal to \mu_o times the net current threading the loop.

\oint \vec B \cdot d\vec l=\mu_o I.

In case of a circular loop, the directions of magnetic field and the line element d\vec l, both are along the tangent of the loop at that point, therefore, \vec B\cdot d\vec l = B\ dl.

\oint \vec B \cdot d\vec l = \oint B\ dl = B\oint dl.\\

\oint dl is the circumference of the Amperian loop = 2\pi r

Therefore,

B\ 2\pi r=\mu_o I\\B=\dfrac{\mu_o I}{2\pi r}.

It is the magnetic field due to a current carrying wire at a distance r from it.

For the first wire, passing through the origin:

Consider an Amperian loop of radius 3.510 m, concentric with the axis of the wire, such that it passes through the point where magnetic field is to be found, therefore, r_1 = 3.510\ m.

The magnetic field at the given point due to this wire is given by:

B_1 = \dfrac{\mu_o I_1}{2\pi r_1}\\=\dfrac{4\pi \times 10^{-7}\times 250}{2\pi \times 3.510}=1.42\times 10^{-5}\ T.

For the first wire, passing through the y-axis:

Consider an Amperian loop of radius (3.510+1.8) m = 5.310 m,  concentric with the axis of the wire, such that it passes through the point where magnetic field is to be found, therefore, r_2 = 5.310\ m.

The magnetic field at the given point due to this wire is given by:

B_2 = \dfrac{\mu_o I_2}{2\pi r_2}\\=\dfrac{4\pi \times 10^{-7}\times 50}{2\pi \times 5.310}=1.88\times 10^{-6}\ T.

The directions of current in both the wires are opposite therefore, the directions of the magnetic field due to both the wires are also opposite to that of each other.

Thus, the net magnetic field at r_r=-3.510\ m is given by

B=B_1-B_2 = 1.42\times 10^{-5}-1.88\times 10^{-6}=1.232\times 10^{-5}\ T.

6 0
3 years ago
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