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scoundrel [369]
3 years ago
9

A line passes through the points (-10,-5) and (20,10) what is the equation of the line A. y=5x B.Y=2x C.1/2 x Dy=1/5 x

Mathematics
2 answers:
quester [9]3 years ago
7 0
The correct answer is C
Assoli18 [71]3 years ago
7 0

Answer:

C. y = ½x

Step-by-step explanation:

<em>Step 1</em>. Find the slope of the line

The general equation for a straight line is

y = mx + b

The slope m is

m =(y₂ -y₁)/(x₂/x₁)

Your points are (-10, -5) and (20, 10).

m = [10 – (-5)]/[20 – (-10)]     Remove inner parentheses

m  = (10+5)/(20 + 10)

m = 15/30

m = ½

===============

<em>Step 2</em>. Find the equation of the line

Substitute the point (20, 10) into the general equation.

10 = ½×20 + b

10 = 10 + b

b = 0

The equation of the line is y = ½x.

The graph shows your line passing through your two points with a slope

m = ½ and a y-intercept at (0, 0).


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8 0
4 years ago
Use the graph of f '(x) below to find the x values of the relative maximum on the graph of f(x):
Lana71 [14]

Answer:

You have relative maximum at x=1.

Step-by-step explanation:

-Note that f' is continuous and smooth everywhere. f therefore exists everywhere on the domain provided in the graph.

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Looking at the graph the switch points are at x=0, x=1, and x=2.

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At x=1, we have f' is greater than 0 before x=1 and that f' is less than 0 after x=1. That means f is increasing to decreasing here. There would be a relative maximum at x=1.

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