Answer:
The correct answer is - 2Cu + 4HBr → 2H[CuBr2] + H2
Explanation:
Copper (Cu) and hydrobromic acid (HBr), which is a dissolved form of hydrogen bromide in the water, react and produce hydrogen dibromidocuprate (I) and hydrogen molecules.
The complete and balanced equation is -
2Cu + 4HBr → 2H[CuBr2] + H2
This reaction takes place in the medium of ester. Copper is in the suspension form in this reaction.
Thus, the correct answer is - 2Cu + 4HBr → 2H[CuBr2] + H2
A natural decay of nuclides occurs in: A.) random manner.
160gof CO2×1molof CO2\44g of CO2×1mole of C\1mol of CO2×12g of C\1mole of C=
43.63g of C
