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Lena [83]
4 years ago
11

What is an orbital?

Chemistry
2 answers:
stepan [7]4 years ago
8 0
A space around an atom that can contain up to two electrons. different types of orbitals have different shapes
juin [17]4 years ago
6 0

Answer:

Relating to orbit or orbits

Explanation:

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What type of words should you include when you write your hypothesis
nignag [31]

Answer:

An if/then statement. If ____happens, then _____ happens.

Explanation:

7 0
3 years ago
Read 2 more answers
g Using Newman projections, draw the most stable conformation for each of the following compounds. (a) 3-methyl pentane, viewed
Marysya12 [62]

Answer:

Using Newman projections, draw the most stable conformation for each of the following compounds.

(a) 3-methyl pentane, viewed along with the C2-C3 bond.

(b) 3,3-dimethyl hexane, viewed along with the C3-C4 bond.

Explanation:

(a) The structure of 3-methyl pentane is shown below:

In Newman projection, the most stable conformation is staggard conformation.

In staggard conformation, the torsional strain is very less compared to eclipsed conformation.

(b)3,3-dimethyl hexane, viewed along with the C3-C4 bond.

3 0
3 years ago
4-hydroxyl and 5- hydroxyl aldehydes exist primarily as a cyclic hemiacetals.draw the structures formed from 4-hydroxyl butanal
svetoff [14.1K]
Attached is the structure of 4 hydroxybutanal both in linear form and hemiacetal form

6 0
3 years ago
Why does a solution of acid and sodium thiosulfate go cloudy
klemol [59]
The soulustion. turn cloudy due to the precipitation of Sulphur.
4 0
4 years ago
A calorimeter that measures an exothermic heat of reaction by the quantity of ice that can be melted is called an ice calorimete
victus00 [196]

Answer:

-892.1 kJ/mol is the change in enthalpy for this reaction.

Explanation:

The heat required to melt the ice or heat of fusion =\Delta H_{fus}=333.5 J/g

Mass of an ice = 10.7 g

Amount of heat required to melt 10.7 grams of ice at 0 degrees Celsius: Q

Q=10.7 g\times 333.5 J/g=3,568.45 J

CH_4+2O_2\rightarrow CO_2+2H_2O, ΔH = ?

Heat released on combustion of 0.00400 moles of methane = Q'= -Q

Q' = -3,568.45 J = -3.568 kJ ( 1J = 0.001 kJ)

Change in enthalpy for this reaction = ΔH

\Delta H=\frac{Q'}{0.00400 mol}=\frac{-3.568 kJ}{0.00400 mol}=-892.1 kJ/mol

-892.1 kJ/mol is the change in enthalpy for this reaction.

4 0
3 years ago
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