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3 years ago

What is the greatest common factor of 20, 50, and 25

Mathematics

2 answers:

steposvetlana [31]3 years ago

5 0

Answer:

Step-by-step explanation:

Harrizon [31]3 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

There are 3 3/4 cookies. if there is 1/4 of a cookie in each bag, how many bags are there?

Svetlanka [38]

Answer:

15 bags

Step-by-step explanation:

3 = 12/4

3 3/4 = 3+3/4 = 12/4 + 3/4 = (12+3)/4 = 15/4

(15/4) ÷ (1/4) = 15

5 0

2 years ago

The eccentricity e of an ellipse is defined as the number c/a, where a is the distance of a vertex from the center and c is the

Anna71 [15]

Answer:

Check below, please.

Step-by-step explanation:

Hi, there!

Since we can describe eccentricity as $e=\frac{c}{a}$

a) Eccentricity close to 0

An ellipsis with eccentricity whose value is 0, is in fact, a degenerate one almost a circle. An ellipse whose value is close to zero is almost a degenerate circle. The closer the eccentricity comes to zero, the more rounded gets the ellipse just like a circle. (Check picture, please)

$\frac{x^2}{a^2} +\frac{y^2}{b^2} =1 \:(Ellipse \:formula)\\a^2=b^2+c^2 \: (Pythagorean\: Theorem)\:a=longer \:axis.\:b=shorter \:axis)\\a^2=b^2+(0)^2 \:(c\:is \:the\: distance \: the\: Foci)\\\\a^2=b^2 \\a=b\: (the \:halves \:of \:each\:axes \:measure \:the \:same)$

b) Eccentricity =5

$5=\frac{c}{a} \:c=5a$

An eccentricity equal to 5 implies that the distance between the Foci has to be five (5) times larger than the half of its longer axis! In this case, there can't be an ellipse since the eccentricity must be between 0 and 1 in other words:

$If\:e=\frac{c}{a} \:then\:c>0 , and\: c>0 \:then \:1>e>0$

c) Eccentricity close to 1

In this case, the eccentricity close or equal to 1 We must conceive an ellipse whose measure for the half of the longer axis a and the distance between the Foci 'c' they both have the same size.

$a=c\\\\a^2=b^2+c^2\:(In \:the\:Pythagorean\:Theorem\: we \:should\:conceive \:b=0)$

$Then:\\\\a=c\\e=\frac{c}{a}\therefore e=1$

7 0

3 years ago

a ribbion is 3 2/3 yards long. Mae needs to cut the ribbion into pieces that are 2/3 yard long.how much ribbion will be left aft

Lemur [1.5K]

To answer this question you need to divide to get the number of pieces and then multiply whats leff by 3 2/3.

Divide 3 2/3 by 2/3. There are a few ways to do this but I am going to turn 3 2/3 into an improper fraction and then divide.

So $3\frac{2}{3} = \frac{11}{3}$
Now divide
$\frac{\frac{11}{3}}{\frac{2}{3}}$
$\frac{11}{3} \times \frac{3}{2} = \frac{11}{2} = 5\frac{1}{2} = 5.5$

We can see she can get 5.5 pieces at 2/3. So .5 is going to be left over so we ask our self, what is .5 of 3 2/3? We times .5 by 3 2/3 = 1.83 yards left. If you want it into a fraction, it would be $1\frac{83}{100}$ yards left