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fomenos
3 years ago
6

Which linear function shows a direct variation? Graph A B C or D

Mathematics
2 answers:
8_murik_8 [283]3 years ago
7 0

Answer:

It is D

Step-by-step explanation:

found it ...

Yanka [14]3 years ago
7 0

Answer:

Graph D is correct

Step-by-step explanation:

Direct variations pass through the origin or (0,0)

Thus, Graph D is correct

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A company plans to sell a new type of cleaner for $280 each. The estimated cost, y, of manufacturing the cleaners is a function
Minchanka [31]
Suppose x is sold, $280 each , and y is the total financial cost. The first equation in the system is then certainly y = 280x.

The vertex form  <span>y-k = a(x-h)^2 where (h,k) is the vertex, and y is the y-intercept.

So, plug the values in.
</span><span>11,000-24,000 = a(0-500)^2
-13,000=250,000a
a=-0.052

y-</span><span>24,000 = -0.052(x-500)^2
y= </span><span>-0.052(x-500)^2 + 24,000
This is the second equation in the system.

The answer is then A, which contain the system </span><span>of equations which can be used to determine must be sold for the company to make a profit.</span>
4 0
3 years ago
In a class of 147 students, 95 are taking math (M), 73 are taking science (S), and 52 are taking both math and science. What is
Marina86 [1]
95/294 orrr 0.3231 And you just round that to the nearest 10th
5 0
3 years ago
(x+2)(x2 - 2x+4)expand and simplify​
Ksenya-84 [330]

Answer:

Step-by-step explanation:

2x2 is 4

5 0
3 years ago
help please I need these finished by today!
iris [78.8K]

Answer:

im pretty sure its D

Step-by-step explanation:

4 0
3 years ago
Anybody know the correct answer?
earnstyle [38]

Since \csc^2{x}=\frac{1}{\sin^2{x}} and \cot^2{x}=\frac{\cos^2{x}}{\sin^2{x}}, we can rewrite the right side of the equation as

\frac{1}{\sin^2{x}}-\frac{\cos^2{x}}{\sin^2{x}} =\frac{1-\cos^2{x}}{\sin^2{x}}

Using the identity \sin^2{x}+\cos^2{x}=1, we can subtract \cos^2{x} from either side to obtain the identity \sin^2{x}=1-\cos^2{x}

substituting that into our previous expression, the right side of our equation simply becomes

\frac{\sin^2{x}}{\sin^2{x}}=1

We can now write our whole equation as

3\tan^2{x}-2=1

Adding 2 to both sides:

3\tan^2{x}=3

dividing both sides by 3:

\tan^2{x}=1

\tan{x}=\pm1

When 0 ≤ x ≤ π, tan x can only be equal to 1 when sin x = cos x, which happens at x = π/4, and it can only be equal to -1 when -sin x = cos x, which happens at x = 3π/4

4 0
3 years ago
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