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3 years ago

14

The Milky Way galaxy contains interstellar matter that may a. Form new galaxies b. Form new stars c. Form new universes D. Form

new constellations

1 answer:

Nana76 [90]3 years ago

3 0

I think the answer is D but I’m not sure

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the rover uses 4GHz frequency to transmit the picture. The rover’s transmission power is 200W. The transmission antenna gain is

Gnoma [55]

Answer:

A rover uses 4GHz frequency to transmit a picture. The rover’s transmission power is 200W. Distance = 55*10^9m. The transmission antenna gain is 10,000 and the receiving antenna gain is 100,000. What is the received signal strength at the Earth’s station, in W (assume Pi = 3.14)?

= 31.5 db

Explanation:

Path loss = 20㏒₁₀(4πdf / c)

= 20㏒₁₀(d) + 20㏒₁₀(f) - 20㏒₁₀(4π / c)

= 20㏒₁₀(55 × 10⁹) + 20㏒₁₀(4000) - 147.5

= (20 × 77.4) + 20 × 3.6 - 147.5

= 154 + 72 - 147.5

= 78.5 DB

Received signal strength(power)

Pr = Pt + Gt + Gr - Lp dBW

= 20 + 40 + 50 - 78.5

= 31.5 db

7 0

3 years ago

When you graph the motion of an object, you put _____ on the horizontal X axis and ____ on the vertical Y axis

wel

It depends upon the type of graph that you are talking about,

If the graph is Velocity - Time graph, then time lies on the X axis and speed on the Y axis.

If it is Distance - Time graph, the time lies on the X axis and distance on the Y axis.

But generally, it is ALWAYS TIME IN THE ‘X’ AXIS AND DISTANCE ON THE ‘Y’ AXIS.

Let me know if you have any doubts by either commenting or messaging me

7 0

3 years ago

Dr. Grey performed an experiment to test how temperature affects activity levels in mice. She put one group of mice in a cold en

katen-ka-za [31]

Answer:

answer is A

Explanation:

7 0

3 years ago

The radioactive element radium (Ra) decays by a process known asalpha decay,in which the nucleus emits a helium nucleus. (Factoi

tamaranim1 [39]

<u>Answer:</u> The energy released in the decay process is $4.6800\times 10^{11}J$

<u>Explanation:</u>

The equation for the alpha decay of Ra-226 follows:

$_{88}^{226}\textrm{Ra}\rightarrow _{2}^{4}\textrm{He}+_{86}^{222}\textrm{Rn}$

To calculate the mass defect, we use the equation:

Mass defect = Sum of mass of product - Sum of mass of reactant

$\Delta m=(m_{Rn}+m_{He})-(m_{Ra})$

We know that:

$m_{Rn}=222.0176u\\m_{Ra}=226.0254u\\m_{He}=4.0026u$

Putting values in above equation, we get:

$\Delta m=(222.0176+4.0026)-(226.0254)=-0.0052g=-5.2\times 10^{-6}kg$

(Conversion factor: 1 kg = 1000 g )

To calculate the energy released, we use Einstein equation, which is:

$E=\Delta mc^2$

$E=(-5.2\times 10^{-6}kg)\times (3\times 10^8m/s)^2$

$E=-4.6800\times 10^{11}J$

Hence, the energy released in the decay process is $4.6800\times 10^{11}J$

8 0

3 years ago

Another unfortunate bug splatters on the windshield of a moving car. Which has the greater change in momentum---the bug or the c

bija089 [108]

Answer:

The change in momentum for the bug and the car will be equal, impulses will be equal in opposite directions and the bug will have a greater acceleration compared to the car, because it has a smaller mass.

Explanation:

Hope this helps..

4 0

3 years ago