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Eddi Din [679]
3 years ago
8

If the pelican was traveling 8.79 m/s but was only 2.7 m above the water, how far would the fish travel horizontally before hitt

ing the water below?
Physics
1 answer:
Gemiola [76]3 years ago
3 0

Answer:

6.52m

Explanation:

The horizontal distance travelled is known as its range. This is expressed as;

Range = u* √2H/g

u is the speed of the pelican

H is the maximum height

g is the acceleration due to gravity

Range = 8.79*√2(2.7)/9.8

Range = 8.79 * √5.4/9.8

range = 8.79*√0.5510

Range = 8.79*0.7423

Range = 6.52

Hence the fish will travel 6.52m before hitting the water below

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6 0
3 years ago
A car with a mass of 1,500 kg requires a centripetal force of 640 N to safely follow a circular curve in the road at 13.4 m/s. W
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<h2>Answer</h2>

Radius is 421 m.

<u>Explanation </u>

A car with a mass of 1,500 kg requires a centripetal force of 640 N to safely follow a circular curve in the road at 13.4 m/s. Therefore, for radius we use formula which is Fc = mv ^ 2 / r,

As mass = m = 1500kg,

Centripetal force = Fc = 640N,

Velocity = v = 13.4 m / s

By putting values, Fc = mv ^ 2 / r,

r = mv ^ 2 / Fc,

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=> r = ( 1500kg ) . ( 179.56 ) / 640,

r = 269340 / 640,

=> r = 420.84 m.

Radius is 421 m.

8 0
3 years ago
Read 2 more answers
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