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3 years ago

Square root of 45 in radical form

Mathematics

1 answer:

AfilCa [17]3 years ago

4 0

Answer:

3 $\sqrt{5}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Given

$\sqrt{45}$

= $\sqrt{9(5)}$

= $\sqrt{9}$ × $\sqrt{5}$

= 3 $\sqrt{5}$

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A walk-in medical clinic believes that arrivals are uniformly distributed over weekdays (Monday through Friday). It has collecte

allsm [11]

Answer:

The degrees of freedom are given by;

$df =n-1= 5-1=4$

The significance level is 0.1 so then the critical value would be given by:

$F_{cric}= 7.779$

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays

Step-by-step explanation:

For this case we have the following observed values:

Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100

For this case the expected values for each day are assumed:

$E_i = \frac{100}{5}= 20$

The statsitic would be given by:

$\chi^2 = \sum_{i=1}^n \frac{(O_i-E_i)^2}{E_i}$

Where O represent the observed values and E the expected values

The degrees of freedom are given by;

$df =n-1= 5-1=4$

The significance level is 0.1 so then the critical value would be given by:

$F_{cric}= 7.779$

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays

5 0

3 years ago

I always get these mixed up, can someone help me?

jolli1 [7]

Answer:

The answer is

1_ side angle side

2_angle side angle

3_ angle angle side

4_ side side side

4 0

3 years ago

The total of 26, 78, 198, 475 and 620 is

MissTica

The answer is 1,397

26+78+198+475+620=1,397

8 0

4 years ago

Read 2 more answers

Which cube root function is always decreasing as x increases?

Anna007 [38]

We shall proceed in graphical method

Graph all 4 functions

Graph 4

Reason:-

It depends upon coefficient

In graph 4 the coefficient outside root is negative so it is decreasing

7 0

2 years ago

Solve sin^4(x)+cos^4(x)=cos4x

ICE Princess25 [194]

$\sin^4x=(\sin^2x)^2=\left(\dfrac{1-\cos2x}2\right)^2=\dfrac{1-2\cos2x+\cos^22x}4$
$\cos^4x=(\cos^2x)^2=\left(\dfrac{1+\cos2x}2\right)^2=\dfrac{1+2\cos2x+\cos^22x}4$

$\implies \sin^4x+\cos^4x=\dfrac{2+2\cos^22x}4=\dfrac{1+\cos^22x}2$

$\cos^22x=\dfrac{1+\cos4x}2$
$\implies\sin^4x+\cos^4x=\dfrac{1+\frac{1+\cos4x}2}2=\dfrac{3+\cos4x}4$

So the equation reduces to

$\dfrac{3+\cos4x}4=\cos4x$
$\dfrac34=\dfrac34\cos4x$
$\cos4x=1$

We have $\cos\theta=1$ whenever $\theta=0+2k\pi=2k\pi$ , where $k$ is any integer. This means for this equation we have solutions at

$4x=2k\pi\implies x=\dfrac{k\pi}2$

6 0

4 years ago