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Morgarella [4.7K]
3 years ago
9

Potassium-40 has a half-life of approximately 1.25 billion years. approximately how many years will pass before a sample of pota

ssium-40 contains one-sixteenth the original amount of parent isotope?
Chemistry
2 answers:
mojhsa [17]3 years ago
4 0
In a first-order chemical reaction, the half-life of the reactant is computed by ln(2)/λ/.Where:λ is the reaction rate constant.
In terms of radioactive decay, the half-life is the extent of time after which there is a 50% probability that an atom will have completed a nuclear decay.
Since (1/2)^4 = 1/16, that would require 4 half-lives, which is 5 billion years.
astraxan [27]3 years ago
4 0

Answer: It will take 5 billion years for the parent isotope to get reduced to one-sixteenth of its original amount.

Explanation:

Initial amount of an isotope =N_o

Amount left after the radio decay = N=\frac{N_o}{16}=0.0625 N_o

Decay constant= \lambda

Half life of the sample: t_{\frac{1}{2}}=1.25 billion years

Years pass before a sample of potassium-40 contains one-sixteenth the original amount of parent isotope be ,t= T

\lambda =\frac{0.693}{1.25 \text{billion years}}=0.5544 \text{billion years}^{-1}

N=N_o\time e^{-\lambda t}

\ln[\frac{N_o}{16}]=\ln[N_o]-0.5544 \text{billion years}^{-1}\times T

\ln[\frac{1}{16}]=-0.5544 \text{billion years}^{-1}\times T

-2.7725=-0.5544\text{billion years}^{-1}\times t

T=\frac{-2.7725}{-0.5544\text{billion years}^{-1}}=5.00 \text{billion years}

It will take 5 billion years for the parent isotope to get reduced to one-sixteenth of its original amount.

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A quantity of gas has a volume if 400.0 ml when confined under a pressure of 600.0mm Hg. What will be the new volume of the gas
den301095 [7]

Answer:

1200 mL

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Initial volume (V1) = 400 mL.

Initial pressure (P1) = 600 mmHg.

Final volume (V2) =..?

Final pressure (P2) = 200 mmHg

Step 2:

Determination of the final volume i.e the new volume of the gas.

Considering the question given, we understood that the temperature is constant. Therefore the gas is obeying Boyle's law. Using the Boyle's law equation, the new volume is obtained as follow:

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Explanation:

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