Answer:
All are correct
Explanation:
1) The angular momentum quantum number, l, are the subshells within a shell (principle quantum number) it talks about the "form" of an orbital, the number itself tells you about the number of angular nodes (a plane without electronic density). It starts at l=0 where you don't see any nodes and it takes the form of an sphere, and we knowing it bu another name an s-orbital. It takes values up to n-1.
l=0 (sphere - s-orbital)
l=1 (p-orbital)
l=2 (d-orbital)
2) The magnetic quatum number, ml relates to the number of orbitals within a subshell then it is related with l, taking values form -l to l incluing 0.
For l=0 (s-orbital) ml=0
For l=1 (p-orbital) ml=1,0,-1
For l=2 (d-orbital) ml=2,1,0,-1,-2
3) In every shell we are restricted by the total number of nodes of any orbital. Then if we want a d-orbital with l=3 we need at least 3 plane nodes only achievable with n=3 at least.
Hi.
I did some digging and I think I found what you're looking for.
I found this on Q(uizlet)
basic or acidic conditions and the reactants must be heated.
~
Answer:
204.73K
Explanation:
the formula : PV=nRT
n=4
P=5.6 atm
V=12 L
R=0.08206 L atm mol-1 K-1
T=?
So, if you plug it in, you will get:-
T=PV/nR
T=(5.6 atm)(12 L)/(4 mol)(0.08206 L atm mol-1 K-1)
T=204.73 K
hope this is correct!
2 hydrogen and 1 oxygen makes water
The correct answer to
the question that is stated above is letter c, <span> the outer electron shell.</span>
Valence electrons occur<span> in the outermost shells of an </span>atom.
>> <span>Valence electrons are </span>electrons<span> that are associated with an </span>atom<span>, and that can participate in the formation of a </span>chemical bond.
