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Norma-Jean [14]
3 years ago
11

Find the resultant of two components, 3km west and 4 km south. How do I solve this using the Pythagorean theorem?

Physics
1 answer:
Rasek [7]3 years ago
3 0

Answer:5

Explanation:

a=3

b=4

c=√(a²+b²)

c=√9+16

c=√25

c=5

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Any help would be great! Thank you x<br><br><br> Giving brainliest answer xoxo
garri49 [273]

Answer:

A vacuum would have been created. I hope this helps have a great day

3 0
3 years ago
A solid non-conducting sphere of radius R carries a charge Q distributed uniformly throughout its volume. At a radius r (r &lt;
Svet_ta [14]

Answer:  

Hence the answer is E inside = KQr_{1} /R^{3}.

Explanation:  

E inside = KQr_{1} /R^{3}  

so if r1 will be the same then  

E  \begin{bmatrix}Blank Equation\end{bmatrix} proportional to 1/R3  

so if R become 2R  

E becomes 1/8 of the initial electric field.

8 0
2 years ago
Read 2 more answers
In deep space there is very little friction once they are launched into a probe into deep space where there are no external forc
BabaBlast [244]
Continue on the momentum it has. The probe will continue in the same direction it is moving because there are no forces to act against it. I think this is the answer you are looking for...?
3 0
3 years ago
Read 2 more answers
Which one of the following does not accurately describe the universal gravitational law? Question 10 options: A) Gravitational f
just olya [345]

Answer:

Choice C seems to be the right answer.

Explanation:

5 0
3 years ago
Read 2 more answers
A professor sits at rest on a stool that can rotate without friction. The rotational inertia of the professor-stool system is 4.
Anestetic [448]

Answer:

\omega=0.37 [rad/s]  

Explanation:

We can use the conservation of the angular momentum.

L=mvR

I\omega=mvR

Now the Inertia is I(professor_stool) plus mR², that is the momentum inertia of a hoop about central axis.

So we will have:

(I_{proffesor - stool}+mR^{2})\omega=mvR

Now, we just need to solve it for ω.

\omega=\frac{mvR}{I_{proffesor-stool}+mR^{2}}

\omega=\frac{1.5*2.7*0.4}{4.1+1.5*0.4^{2}}      

\omega=0.37 [rad/s]  

I hope it helps you!

5 0
3 years ago
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