1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yaroslaw [1]
3 years ago
9

All of the noble gases, Group 18, have eight valence electrons in its outer shell (excluding helium which only has two). Which o

f these would represent the oxidation number of the noble gases such as xenon and argon?
Physics
2 answers:
ikadub [295]3 years ago
6 0

Answer:

Zero or +2

Explanation:

The noble gases already have a avplete outermost shell. They are the least reactive elements of earth?

Their normal oxidation number is zero but some have been shown to be reactive.

Anna007 [38]3 years ago
5 0

Answer:

Explanation:

Since oxidation number is derived from the number of electron in the outermost shell of an element and further more this oxidation number is a function of how much electron is needed by an element to achieve a duplet ( He) or octet configuration ( complete outer most shell which is the attributes of group  18 elements or noble gases) and they don't readily react with any compound.. Since Xenon and argon are noble gases , they will have their outer most shell completely feel hence their oxidation number will be zero (0)

You might be interested in
If we decrease the distance an object moves we will
hodyreva [135]
Length of object . how much distance increase or decrease force
7 0
3 years ago
Read 2 more answers
A ball is dropped from a height of 10m. At the same time, another ball is thrown
soldi70 [24.7K]

5.1 m

Explanation:

Let's set the ground as our reference point. Let's also call the dropped ball to be ball #1 and its height above the ground at any time t is given by

y_1 = 10 - \frac{1}{2}gt^2 (1)

where 10 represents its initial height or displacement of 10 m above the ground. At the same time, the displacement of the second ball with respect to the ground y_2, is given by

y_2 = v_0t - \frac{1}{2}gt^2 (2)

At the instant the two balls collide, they will have the same displacement, therefore

y_1 = y_2 \Rightarrow 10 - \frac{1}{2}gt^2 = v_0t - \frac{1}{2}gt^2

or

v_0t = 10\:\text{m}

Solving for t, we get

t = \dfrac{10\:\text{m}}{v_0} = \dfrac{10\:\text{m}}{10\:\text{m/s}} = 1\:\text{s}

We can use either Eqn(1) or Eqn(2) to hind the height where they collide. Let's use Eqn(1):

y_1 = 10\:\text{m} - \frac{1}{2}(9.8\:\text{m/s}^2)(1\:\text{s})^2

\:\:\:\:\:\:\:= 5.1\:\text{m}

8 0
2 years ago
For the meter stick shown in figure 10-4, the force F1 10.0 N acts at 10.0 cm. What is the magnitude of torque due to F1 about a
Phantasy [73]

Torque is equal position vector times (r) times force vector (F).  Since F= 10 N and r = 0.1 m, so the torque is equal to (10 N) x ( 0.1 m) = 1Nm. The direction of the torque would be into the screen, clockwise rotation.

8 0
3 years ago
Read the article Watering Livestock with Renewable Energy.
DaniilM [7]

Answer:

D. Wind and solar energy help save money and reduce air pollution.

Explanation:

7 0
2 years ago
Read 2 more answers
In a microwave oven, electrons describe circular motion in a magnetic field within a special tube called amagnetron; as you'll l
QveST [7]

Answer:

The magnetic field strength and the electrons' energy are 0.077 T and 0.8906 eV.

Explanation:

Given that,

Diameter = 2.62 mm

Frequency = 2.15 GHz

(A). We need to calculate the magnetic field strength

Using formula of the magnetic field strength

B=\dfrac{2\pi mf}{e}

Where, f = frequency

e = charge of electron

Put the value into the formula

B=\dfrac{2\times3.14\times9.1\times10^{-31}\times2.15\times10^{9}}{1.6\times10^{-19}}

B=0.077\ T

(B). We need to calculate the energy of electron

Using formula of energy

E=\dfrac{1}{2}m(r\omega)^2

E=\dfrac{1}{2}\times9.1\times10^{-31}\times(1.31\times10^{-3}\times2\pi\times2.15\times10^{9})^2

E=1.4249\times10^{-16}\ J

The energy in eV

1 eV=1.6\times10^{-16}\ J

E=\dfrac{1.4249\times10^{-16}}{1.6\times10^{-16}}

E=0.8906\ eV

Hence, The magnetic field strength and the electrons' energy are 0.077 T and 0.8906 eV.

5 0
3 years ago
Other questions:
  • A car traveling at 30m/s screeches to a halt, leaving 55 m long skid marks. what was the cars acceleration while braking
    12·1 answer
  • How would you describe the magnetic field produced by a current in a straight wire?
    7·2 answers
  • In general, as the energy of a sound wave increases, A. the sound gets softer and then louder. B. the sound gets louder. C. the
    10·2 answers
  • PLEASE HELP ME!!!!!!!!!!
    12·1 answer
  • A pole-vaulter converts the kinetic energy of running to elastic potential energy in the pole, which is then converted to gravit
    12·1 answer
  • A wire long and with mass is positioned horizontally near the earth's surface and perpendicular to a horizontal magnetic field o
    10·1 answer
  • Tim and Rick both can run at speed vr and walk at speed vw, with vr>vw. They set off together on a journey of distance D. Ric
    10·1 answer
  • How does the entire nervous system allow our bodies to interact with our world? Your response must include the following terms:
    8·2 answers
  • What would happen if the louisiana purchase did not double the United States?
    13·1 answer
  • Velocity and acceleration are both vectors; they have a
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!