Answer:
4032 different tickets are possible.
Step-by-step explanation:
Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.
To find : How many different tickets are possible ?
Solution :
In the first race there are 9 ways to pick the winner for first and second place.
Number of ways for first place - 
Number of ways for second place - 
In the second race there are 8 ways to pick the winner for first and second place.
Number of ways for first place - 
Number of ways for second place - 
Total number of different tickets are possible is


Therefore, 4032 different tickets are possible.
Answer:
A
Step-by-step explanation:
the equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
(x + 9)² + (y - 6)² = 10² is in this form
with centre = (- 9, 6) → A
Using elimination you can eliminate 'y' to find x first.
4x=24
+ 5x=12
-------------
9x=36
9/9 x=36/9
X=4
Next use substitution to plug 4 back in to 'x'
4(4)+y=24
16+y=24
-16 -16
------------
Y=8
X is 4 and Y is 8
(x-8)^2+y^2=225 I'm not able to factor it