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Anna007 [38]
3 years ago
14

which two objects have stored energy A)a ball rolling on the ground B) a small rock sitting on top of a big rock C)a stretched r

ubber band D) a stone lying on the ground
Physics
2 answers:
Alik [6]3 years ago
5 0
B).  <span>a small rock sitting on top of a big rock has a little bit of
stored gravitational potential energy

C).  a stretched rubber band has some stored elastic energy</span>
Semenov [28]3 years ago
3 0

Answer:

B) a small rock sitting on top of a big rock C)a stretched rubber band

Explanation: Stored energy is also known as potential energy. This is defined as the energy possessed by an object that is stationary, i.e an object that is not in motion.

A stretched rubber band has elastic potential energy.

A small rock sitting on top of a big rock has gravitational potential energy because it is stationary and it is located at a certain height above the earth's surface.

However, taking the earth's surface as a reference, the stone lying directly on the earth's surface does not have any potential energy even though it is stationary; reason being that it is at a zero height from the earth's surface. This claim can be justified from the simple formula E=mgh which is used to calculate gravitational potential energy.  When height h = 0, then consequently the equation reduces to zero, i.e. potential energy E = 0

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Momentum = ___________.
posledela
The answer must be a mass x velocity
4 0
3 years ago
EXPERTS/ACE and people that wanna help 4 sure only!
mario62 [17]
That first one you have selected (3,-3) works in both equations so it's correct.
good job.

you can do this guess and test method with multiple choice answers. If it works in both equations it is the solution. Otherwise use substitution or elimination to combine the two into one equation in only one variable. Then you can solve for the one variable first and use it to solve for the other.

3 0
3 years ago
A construction worker puts 20 J of energy in to one strike of his hammer on the head of a nail. The energy transferred to drivin
maks197457 [2]

Answer:

The efficiency of the constuction is 9.0

Explanation:

3 0
3 years ago
A car is moving in the positive direction along a straight highway and accelerates at a constant rate while going from point A t
rusak2 [61]

Answer:

The time where the avergae speed equals the instaneous speed is T/2

Explanation:

The velocity of the car is:

v(t) = v0 + at

Where v0 is the initial speed and a is the constant acceleration.

Let's find the average speed. This is given integrating the velocity from 0 to T and dividing by T:

v_{ave} = \frac{1}{T}\int\limits^T_0 {v(t)} \, dt

v_ave = v0+a(T/2)

We can esaily note that when <u><em>t=T/2</em></u><u><em> </em></u>

v(T/2)=v_ave

Now we want to know where the car should be, the osition of the car is:

x(t) = x_A + v_0 t + \frac{1}{2}at^2

Where x_A is the position of point A. Therefore, the car will be at:

<u><em>x(T/2) = x_A + v_0 (T/2) + (1/8)aT^2</em></u>

8 0
3 years ago
A hot air balloon is on the ground, 200 feet from an observer. The pilot decides to ascend at 100 ft/min. How fast is the angle
liq [111]

Answer:

0.0031792338 rad/s

Explanation:

\theta = Angle of elevation

y = Height of balloon

Using trigonometry

tan\theta=y\dfrac{y}{200}\\\Rightarrow y=200tan\theta

Differentiating with respect to t we get

\dfrac{dy}{dt}=\dfrac{d}{dt}200tan\theta\\\Rightarrow \dfrac{dy}{dt}=200sec^2\theta\dfrac{d\theta}{dt}\\\Rightarrow 100=200sec^2\theta\dfrac{d\theta}{dt}\\\Rightarrow \dfrac{d\theta}{dt}=\dfrac{100}{200sec^2\theta}\\\Rightarrow \dfrac{d\theta}{dt}=\dfrac{1}{2}cos^2\theta

Now, with the base at 200 ft and height at 2500 ft

The hypotenuse is

h=\sqrt{200^2+2500^2}\\\Rightarrow h=2507.98\ ft

Now y = 2500 ft

cos\theta=\dfrac{200}{h}\\\Rightarrow cos\theta=\dfrac{200}{2507.98}=0.07974

\dfrac{d\theta}{dt}=\dfrac{1}{2}\times 0.07974^2\\\Rightarrow \dfrac{d\theta}{dt}=0.0031792338\ rad/s

The angle is changing at 0.0031792338 rad/s

6 0
3 years ago
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