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Natalija [7]
3 years ago
6

NEED HELP ASAP ONLY HAVE 1 MINUTE !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!!!!!!!!!!!!!
A ------ and a-------- are examples of inclined planes.
CHOICES FOR FIRST BLANK: lever and wedge
CHOICE FOR SECOND BLANK:Pulley and screw
Physics
1 answer:
matrenka [14]3 years ago
5 0

My guess is <u><em>Wedge & Pulley</em></u>

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13 points and brainlyest if possible. Thanks.
nikdorinn [45]
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Suppose that the Sun started shrinking in size, without losing any mass. What would be the effect of the Sun's change on the orb
adell [148]

Answer:

F = G M m / R^2 gravitational force on planet of mass m.

None of these quantities change in the given hypothesis so

there will be no change in the orbit of mass m

3 0
2 years ago
A 4-kg cat is resting on a bookshelf that is 2 m high. What is the cats gravitational potential energy relative to the floor if
ra1l [238]
The most exact answer is 78.4J also in this kind of options we can say answer "d"
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3 years ago
Say you want to make a sling by swinging a mass M of 2.3 kg in a horizontal circle of radius 0.034 m, using a string of length 0
ycow [4]

Answer:

T = 764.41 N

Explanation:

In this case the tension of the string is determined by the centripetal force. The formula to calculate the centripetal force is given by:

F_c=m\frac{v^2}{r}  (1)

m: mass object = 2.3 kg

r: radius of the circular orbit = 0.034 m

v: tangential speed of the object

However, it is necessary to calculate the velocity v first. To find v you use the formula for the kinetic energy:

K=\frac{1}{2}mv^2

You have the value of the kinetic energy (13.0 J), then, you replace the values of K and m, and solve for v^2:

v^2=\frac{2K}{m}=\frac{2(13.0J)}{2.3kg}=11.3\frac{m^2}{s^2}

you replace this value of v in the equation (1). Also, you replace the values of r and m:

F_c=(2.3kg)(\frac{11.3m^2/s^2}{0.034})=764.41N

hence, the tension in the string must be T =  Fc = 764.41 N

5 0
3 years ago
A soccer player kicks a soccer ball initially at rest setting it in motion at a velocity of 30 m/s. If the ball has a mass of 0.
Alchen [17]

Answer:

 F= 600 N

Explanation:

Given that

Initial velocity ,u= 0 m/s

Final velocity ,v= 30 m/s

mass ,m = 0.5 kg

time ,t= 0.025 s

The change in the linear momentum is given as

ΔP= m (v - u)

ΔP= 0.5 ( 30 - 0 ) kg.m/s

ΔP= 15 kg.m/s

We know that from second law of Newtons

F=\dfrac{dP}{dt}

F=\dfrac{\Delta P}{t}

Now by putting the values

F=\dfrac{15}{0.025}\ N

F= 600 N

5 0
3 years ago
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