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mojhsa [17]
3 years ago
12

| A T-ball with a mass of 0.6 kg travels in the

Physics
1 answer:
r-ruslan [8.4K]3 years ago
7 0

Answer:

|I|=6\ Kg.m/s

F=120\ N

Explanation:

Impulse and Momentum

They are similar concepts since they deal with the dynamics of objects having their status of motion changed by the sudden application of a force. The momentum at a given initial time is computed as

p_o=m.v_o

When a force is applied, the speed changes to v_1 and the new momentum is

p_1=m.v_1

The change of momentum is

\Delta p=p_1-p_0=m(v_1-v_o)

The impulse is equal to the change of momentum of an object and it's defined as the average net force applied times the time it takes to change the object's motion

I=F.t=\Delta p

Part 1

The T-ball initially travels at 10 m/s and then suddenly it's stopped by the glove. The final speed is zero, so

\Delta p=0.6\ Kg(0-10\ m/s)=-6\ Kg.m/s

The impulse is

I=\Delta p

I=-6\ Kg.m/s

The magnitude is

|I|=6\ Kg.m/s

Part 2

The force can be computed from the formula

I=F.t

The direction of the impulse the T-ball receives is opposite to the direction of the force exerted by the ball on the glove, thus I_b=6\ kg.m/s

\displaystyle F=\frac{I}{t}=\frac{6\ kg.m/s}{0.05\ s}

\boxed{F=120\ N}

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The British gold sovereign coin is an alloy of gold and copper having a total mass of 7.988 g, and is 22-karat gold 24 x (mass o
matrenka [14]

Answers:

(a) 0.0073kg

(b) Volume gold: 3.79(10)^{-7}m^{3}, Volume cupper: 7.6(10)^{-8}m^{3}

(c) 17633.554kg/m^{3}

Explanation:

<h2>(a) Mass of gold </h2><h2 />

We are told the total mass M of the coin, which is an alloy  of gold and copper is:

M=m_{gold}+m_{copper}=7.988g=0.007988kg   (1)

Where  m_{gold} is the mass of gold and m_{copper} is the mass of copper.

In addition we know it is a 22-karat gold and the relation between the number of karats K and mass is:

K=24\frac{m_{gold}}{M}   (2)

Finding {m_{gold}:

m_{gold}=\frac{22}{24}M   (3)

m_{gold}=\frac{22}{24}(0.007988kg)   (4)

m_{gold}=0.0073kg   (5)  This is the mass of gold in the coin

<h2>(b) Volume of gold and cupper</h2><h2 />

The density \rho of an object is given by:

\rho=\frac{mass}{volume}

If we want to find the volume, this expression changes to: volume=\frac{mass}{\rho}

For gold, its volume V_{gold} will be a relation between its mass m_{gold}  (found in (5)) and its density \rho_{gold}=19.30g/cm^{3}=19300kg/m^{3}:

V_{gold}=\frac{m_{gold}}{\rho_{gold}}   (6)

V_{gold}=\frac{0.0073kg}{19300kg/m^{3}}   (7)

V_{gold}=3.79(10)^{-7}m^{3}   (8)  Volume of gold in the coin

For copper, its volume V_{copper} will be a relation between its mass m_{copper}  and its density \rho_{copper}=8.96g/cm^{3}=8960kg/m^{3}:

V_{copper}=\frac{m_{copper}}{\rho_{copper}}   (9)

The mass of copper can be found by isolating m_{copper} from (1):

M=m_{gold}+m_{copper}  

m_{copper}=M-m_{gold}  (10)

Knowing the mass of gold found in (5):

m_{copper}=0.007988kg-0.0073kg=0.000688kg  (11)

Now we can find the volume of copper:

V_{copper}=\frac{0.000688kg}{8960kg/m^{3}}   (12)

V_{copper}=7.6(10)^{-8}m^{3}   (13)  Volume of copper in the coin

<h2>(c) Density of the sovereign coin</h2><h2 />

Remembering density is a relation between mass and volume, in the case of the coin the density \rho_{coin will be a relation between its total mass M and its total volume V:

\rho_{coin}=\frac{M}{V} (14)

Knowing the total volume of the coin is:

V=V_{gold}+V_{copper}=3.79(10)^{-7}m^{3}+7.6(10)^{-8}m^{3}=4.53(10)^{-7}m^{3} (15)

\rho_{coin}=\frac{0.007988kg}{4.53(10)^{-7}m^{3}} (16)

Finally:

\rho_{coin}=17633.554kg/m^{3}} (17)  This is the total density of the British sovereign coin

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3 years ago
Two students on ice skates stand one behind the other. Student 2 pushes student 1 in the back; both students move away from each
Hatshy [7]

Answer:

forcing in act

Explanation:

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3 years ago
One mole of titanium contains how many atoms?
Vladimir [108]

Answer:

\boxed {\boxed {\sf D. \ 6.02*10^{23} \ atoms}}

Explanation:

One mole of a substance contains the same amount of representative particles. These particles can be atoms, molecules, ions, or formula units. In this case, the particles are atoms of titanium.

Regardless of the particles, there will always be <u>6.02*10²³</u> (also known as Avogadro's Number) particles in one mole of a substance.

Therefore, the best answer for 1 mole of titanium is D. 6.02*10²³ atoms.

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3 years ago
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I Believe The Answer Is C
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7. Describe about the difficultites that would arise due to lack of non-uniformity in measurement. ​
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Answer:

Many difficulties would arise if there was a lack of uniformity in the measurement of various weights and measures between business, industry, individuals and countries. The biggest implications for a lack of uniformity are in health and safety, equity and sustainability.

Explanation:

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6 0
3 years ago
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