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lyudmila [28]
3 years ago
7

A bag contains 9 blue marbles and 3 red marbles. two marbles are drawn at random and at the same time. what is the probability o

f getting two blue marbles
Mathematics
2 answers:
Strike441 [17]3 years ago
7 0
The answer is 9/12 or if simplified, it's 3/4
mr Goodwill [35]3 years ago
3 0

The total number of marbles in the bag are 12 (9 blue marbles and 3 red marbles).

Let "A" be the event that both the drawn marbles are blue.

Therefore, if two marbles are drawn at random and at the same time, then the probability of getting two blue marbles can be calculated as:

P(A)=\frac{9}{12}=\frac{3}{4}

This can also be expressed in terms of percentage as:

P(A)=\frac{3}{4}\times 100=75%

Thus, the required probability is either: \frac{3}{4} or 75%


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expeople1 [14]
The correct answer is B
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1. If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter o
tester [92]

Answer:

Part 1) The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor (see the explanation)

Part 2) The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) The new figure and the original figure are not similar figures (see the explanation)

Step-by-step explanation:

Part 1) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its perimeters is equal to the scale factor

so

The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor

Part 2) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the area of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its areas is equal to the scale factor squared

so

The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) What would happen to the perimeter and area of a figure if the dimensions were changed NON-proportionally? For example, if the length of a rectangle was tripled, but the  width did not change? Or if the length was tripled and the width was decreased by a factor of 1/4?​

we know that

If the dimensions were changed NON-proportionally, then the ratio of the corresponding sides of the new figure and the original figure are not proportional

That means

The new figure and the original figure are not similar figures

therefore

Corresponding sides are not proportional and corresponding angles are not congruent

so

<u><em>A) If the length of a rectangle was tripled, but the  width did not change?</em></u>

Perimeter

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2W ----> P=6L+2W

The perimeter of the new figure is greater than the perimeter of the original figure but are not proportionals

Area

The original area is A=LW

The new area  would be A=(3L)(W) ----> A=3LW

The area of the new figure is three times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

<u><em>B) If the length was tripled and the width was decreased by a factor of 1/4?</em></u>

Perimeter

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2(W/4) ----> P=6L+W/2

The perimeter of the new figure and the perimeter of the original figure are not proportionals

Area

The original area is A=LW

The new area  would be A=(3L)(W/4) ----> A=(3/4)LW

The area of the new figure is three-fourth times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

5 0
2 years ago
Solve t-v/r=k, for v
Arisa [49]

Answer:

t-v/r = k

t-k = v/r

v = r(t-k)

Hope this helps!

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The third answer option is correct.  sqrt(x) = x^(1/2).  So sqrt(121) = 121^(1/2).
7 0
3 years ago
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