The equation of direct variation is,

Substitute the values of <em>y</em> and <em>x</em>.

So, the obtained equation will be <em>y</em>=1.35(x).
Let's check with the values of <em>x</em>.
1) If <em>x</em>=4

2) If <em>x</em>=2

3) If <em>x</em>=-2
Answer:
y-5=3/7(x-3)
Step-by-step explanation:
the 3/7 is a fraction
Cos(<span>θ) < 0, so we know it would be in Quadrant 2 or 3
then csc(</span>θ) = 257, but csc(θ) =

= 257
==> sin(<span>θ) =

it is positive, so now we can determine that is in Quadrant 2
sin(</span>θ) = opp./hyp both of opp and hyp are positive but adj suppose to negative because that way it leads the cos(<span>θ) < 0
</span>cos(<span>θ) = adj/hyp
</span>Pythereom to find the adj:

cosθ =

tanθ =

cos<span>θ = </span>
If we are to write this equation in slope-intercept form, it will be in y = mx + b, where m is the slope of the line and b is the y intercept. We need then to find the slope of the line using 2 points on the line and filling in the slope formula to find the slope. One of the points we can use is (0, 3) which is also the y intercept. The y-intercept is found where x = 0. Where x = 0, y = 3. So b = 3. Now for the slope we will use (0,3) and (4,4):

. Using that m value and that b value we have the equation

. There you go!