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Andreas93 [3]
3 years ago
13

Diego solved an equation by multiplying both sides of the equation by 6. Then he checked that 6 is the correct solution by subst

ituting it back into the equation. Which of the following gives the properties of equality that he used and their correct order?
a)substitution property of equality and multiplication property of equality

b) multiplication property of equality and addition property of equality

c)multiplication property of equality and substitution property of equality

d)transitive property of equality and substitution property of equality
Mathematics
2 answers:
Maslowich3 years ago
8 0
I believe your answer would be c

love history [14]3 years ago
3 0

Answer:

Option C is correct.

Step-by-step explanation:

Diego solved an equation by multiplying both sides of the equation by 6.

Then he checked that 6 is the correct solution by substituting it back into the equation.

The properties that Diego used are :

C: multiplication property of equality and substitution property of equality

The multiplication property of equality states that if we multiply both sides of an equation by the same number, the sides remain equal.

And the substitution property of equality states that if x = y, then x can be substituted in for y in any equation. Similarly, y can be substituted for x in any equation.

Therefore, Diego used both these properties. (Option c)

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\bf A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 1}\implies A=1500(1.04)^1\implies A\approx 1560\\\\\\A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 2}\implies A=1500(1.04)^2\implies A\approx 1622.4\\\\\\A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 3}\implies A=1500(1.04)^3\implies A\approx 1687.3\\\\\\A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 4}\implies A=1500(1.04)^4\implies A\approx 1754.79\\\\\\A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 5}\implies A=1500(1.04)^5\implies A\approx 1824.98

6 0
3 years ago
Prove that the square of an odd number is always 1 more than a multiple of 4
loris [4]

Answer:

By these examples you are able to see that the square of an odd number is always 1 more than a multiple of 4.

Step-by-step explanation:

For examples,

Let's consider squares of 3, 11, 25, 37 and 131.

{3}^{2}  = 9

8 is a multiple of 4, and 9 is more than 8.

{11}^{2}  = 121

120 is a multiple of 4 and 121 is one more than it.

{25}^{2}  = 625

624 is a multiple of 4 and 625 is one more than it.

{37}^{2}  = 1369

1368 is a multiple of 4 and 1369 is one more than 1368.

{131}^{2}  = 17161

17160 is a multiple of 4.

5 0
3 years ago
The triangle shown below has an area of 16 units^2<br> Find x.
Oduvanchick [21]

Answer:

8 units squared

Step-by-step explanation:

Here's the formula of a triangle

base*height divided by 2

So, we know that the base is 4.

We have to work backwards.

16*2 is 32

32 divided by 4 is 8.

Now let's see

8*4 is 32 divided by 2 is 16!

Hope you understand :)

4 0
3 years ago
Read 2 more answers
The length of a rectangle is 4 more than its width. The area of the rectangle is 21m2 . What is the measure of the width?
iris [78.8K]
Length(l)= 4+ w
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so keep in mind Area= Length × width

A= l×w
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The width is 3.5m

so the answer is about 4m
6 0
4 years ago
Read 2 more answers
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ladessa [460]

All you need to do with this problem is convert (3x^5-2)^\frac{1}{2} into a square root. Then you'll get the answer \sqrt{3x^5-2}.

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