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Andreas93 [3]
2 years ago
13

Diego solved an equation by multiplying both sides of the equation by 6. Then he checked that 6 is the correct solution by subst

ituting it back into the equation. Which of the following gives the properties of equality that he used and their correct order?
a)substitution property of equality and multiplication property of equality

b) multiplication property of equality and addition property of equality

c)multiplication property of equality and substitution property of equality

d)transitive property of equality and substitution property of equality
Mathematics
2 answers:
Maslowich2 years ago
8 0
I believe your answer would be c

love history [14]2 years ago
3 0

Answer:

Option C is correct.

Step-by-step explanation:

Diego solved an equation by multiplying both sides of the equation by 6.

Then he checked that 6 is the correct solution by substituting it back into the equation.

The properties that Diego used are :

C: multiplication property of equality and substitution property of equality

The multiplication property of equality states that if we multiply both sides of an equation by the same number, the sides remain equal.

And the substitution property of equality states that if x = y, then x can be substituted in for y in any equation. Similarly, y can be substituted for x in any equation.

Therefore, Diego used both these properties. (Option c)

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Drag each tile to the correct box.
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Answer:

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

Step-by-step explanation:

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

the average rate of change is equal to

\frac{f(b)-f(a)}{b-a}

step 1

Find the average rate of change of function h(x) over interval [3,5]

Looking at the third picture (table)

f(a)=h(3)=4  

f(b)=h(5)=16

a=3

b=5

Substitute

\frac{16-4}{5-3}=6

step 2

Find the average rate of change of function f(x) over interval [3,6]

Looking at the graph

f(a)=f(3)=10  

f(b)=f(6)=35

a=3

b=6

Substitute

\frac{35-10}{6-3}=8.33

step 3

Find the average rate of change of function g(x) over interval [2,3]

we have

g(x)=\frac{1}{5}(4)^x

f(a)=g(2)=\frac{1}{5}(4)^2=\frac{16}{5}  

f(b)=g(3)=\frac{1}{5}(4)^3=\frac{64}{5}

a=2

b=3

Substitute

\frac{\frac{64}{5}-\frac{16}{5}}{3-2}=9.6

therefore

In order from least to greatest according to their average rates of change over those intervals

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

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