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Pani-rosa [81]
3 years ago
12

Use the calculator to approximate

Mathematics
1 answer:
poizon [28]3 years ago
7 0
125.40
What is the x 5 for?
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Four students spent $9.40 on school lunch.at this rate,predict the amount 10 students would spend on the same school lunch
Tom [10]
You will need to know how much each lunch cost
so
9.40  <span>÷ 4  =  2.35
so each  lunch cost 2.35 dollars

now we need to find out how much it will cost for 10 lunches

10 x 2.35 = 23.5

so for 10 lunches it will cost 23.5</span>
8 0
3 years ago
Read 2 more answers
Each school bus going on the field trip holds 36 students and 4 adults.There are 6 filled buses on the field trip.How many peopl
Dvinal [7]

Hello there

36+4=40 people in one bus

In 6 buses how many people?

40•6=240 people are going on the field trip

:D

6 0
3 years ago
alex has a 48 mile trail first half of the time he was biking twice as fast as the second half of the time if he spent 4 hours o
Irina-Kira [14]

Answer:

16 mph

Step-by-step explanation:

Givens:

4 hours total time

48 miles total distance

So our equation should look like this.

48 = 2x(2) + x(2)

Where x = speed second half of trip.

x = 8

x*2 = 16 mph

4 0
3 years ago
Write an equation to represent each graph​
givi [52]

equation for first figure=2x+y=2

equation for second figure= 4x-y=8

(use formula x/a+y/b=1)

where, a=x component and b= y component..

7 0
3 years ago
The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas
saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by s(t) = -t^3+3t^2+7t +4, where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

s(t) = -t^3+3t^2+7t +4

Derivate w.r.t. time,

v(t)=s'(t) = -3t^2+6t+7

It is a quadratic function so its maximum is at vertex of the function.

The x point of the function is given by,

x=-\frac{b}{2a}

Where, a=-3, b=6 and c=7

t=-\frac{6}{2(-3)}

t=-\frac{6}{-6}

t=1

As 1 lie between interval [0,4]

Substitute t=1 in the function,

v(t)= -3(1)^2+6(1)+7

v(t)= -3+6+7

v(1)=10

Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0
3 years ago
Read 2 more answers
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