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Sliva [168]
3 years ago
12

WHAT MASS OF WATER WILL BE PRODUCED FROM 2.70 MOLES OF CA(OH)2 REACTING WITH HCI

Chemistry
1 answer:
Keith_Richards [23]3 years ago
3 0

<u>Answer:</u> The mass of water produced in the reaction is 97.2 grams

<u>Explanation:</u>

We are given:

Moles of calcium hydroxide = 2.70 moles

The chemical equation for the reaction of calcium hydroxide and HCl follows:

Ca(OH)_2+HCl\rightarrow CaCl_2+2H_2O

By Stoichiometry of the reaction:

1 mole of calcium hydroxide produces 2 moles of water

So, 2.70 moles of calcium hydroxide will produce = \frac{2}{1}\times 2.70=5.40mol of HCl

To calculate mass for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of water = 18 g/mol

Moles of water = 5.40 moles

Putting values in above equation, we get:

5.40mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(5.40mol\times 18g/mol)=97.2g

Hence, the mass of water produced in the reaction is 97.2 grams

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Answer:

                       0.50 moles of Cu

Explanation:

                    The balanced chemical equation for given synthetic reaction is,

                                          2 Cu + S → Cu₂S

According to balance chemical equation,

                  1 mole of Cu₂S is produced by  =  2 moles of Cu

So,

          0.25 moles of Cu₂S will be produced by  =  X moles of Cu

Solving for X,

                      X  =  0.25 mol × 2 mol /  1 mol

                      X  =  0.50 moles of Cu

Hence, as the molar ratio of Cu to Cu₂S is 2:1 hence, to produce 0.25 moles of Cu₂S we will need 0.50 moles of Cu.

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1. Convert the following temperatures to K.<br> a) 104 C<br> b) -3 C
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