Answer:
Uranium-233- fission
Plutonium-239- fission
Plutonium-241- fission
Hydrogen-3 fusion
Hydrogen-1 fusion
Helium-3 fusion
Explanation:
In nuclear fission, heavy nuclear disintegrate into smaller nuclei when bombarded with particles such as neutrons. Fission reaction is common among nuclei having a high atomic number such as plutonium and uranium.
Fusion occurs between two light nuclei such as hydrogen or helium. It involves the combination of two lighter elements to give a heavier element with the release of tremendous amount of energy.
Answer:
The mass of xenon in the compound is 2.950 grams
Explanation:
Step 1: Data given
Mass of XeF4 = 4.658 grams
Molar mass of XeF4 = 207.28 g/mol
Step 2: Calculate moles of XeF4
Moles XeF4 = mass XeF4 / molar mass XeF4
Moles XeF4 = 4.658 grams / 207.28 g/mol
Moles XeF4 = 0.02247 moles
Step 3: Calculate moles of xenon
XeF4 → Xe + 4F-
For 1 mol xenon tetrafluoride, we have 1 mol of xenon
For 0.02247 moles XeF4 we have 0.02247 moles Xe
Step 4: Calculate mass of xenon
Mass xenon = moles xenon * molar mass xenon
Mass xenon = 0.02247 moles * 131.29 g/mol
Mass xenon = 2.950 grams
The mass of xenon in the compound is 2.950 grams
Answer: an addition reaction is one where two molecules react together to produce one. in this case a bromine molecule reacts with ethene and one of the bromine atoms is added to ethene
Explanation:
hope this helps :)
Answer:
Iron
Explanation:
Heat released by the metal sample will be equivalent to the heat absorbed by water.
But heat = mass × specific heat capacity × temperature change
Thus;
Heat released by the metal;
= 45.9 g × c ×(95.2 -24.5) , where c is the specific heat capacity of the metal
= 3245.13c joules
Heat absorbed by water;
= 120 g × 4.18 J/g°C × (24.5-21.6)
= 1454.64 joules
Therefore;
3245.13c joules = 1454.64 joules
c = 1454.64/3245.13
= 0.448 J/g°C
The specific heat capacity of the metal sample is 0.448 J/g°C. The metal use is most likely, Iron.
Answer: C, B, A
Explanation:
C is the initial solution, because naoh has not been added yet
B is the midpoint of the titration. naoh has been added to the solution, but it has not fully reacted yet. You can tell that this one is the midpoint because there is still HF- in the diagram, which is not one of the products formed in the reaction.
A is the endpoint because the diagram shows that all products are fully formed. There is an increased amount of Na+ and H2O in the diagram and no HF- left.
PS. I tested this answer on the concentration of acetic acid post-lab (from mcgraw hill) earlier today and it said this was the right answer :) hope this helps
