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Wittaler [7]
3 years ago
5

What is the kinetic energy of a 50-kg child running to catch the school bus at

Physics
2 answers:
Vinvika [58]3 years ago
6 0

Answer:

Option C

100 J

Explanation:

Kinetic energy, KE is given by

KE=0.5mv^{2} where m is the mass and v is the velocity

Substituting 50 Kg for mass, m and 2 m/s for velocity v then we obtain

KE=0.5*50*2^{2}=100 J

Therefore, the child's kinetic energy is equivalent to 100 J

Zepler [3.9K]3 years ago
5 0

Answer:100J

Explanation:

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A 24-cm-diameter vertical cylinder is sealed at the top by a frictionless 15 kg piston. The piston is 90 cm above the bottom whe
abruzzese [7]

Answer:

(A) P_i=3249.41\ Pa

(B) V_f=0.3358\ m

Explanation:

Given:

  • diameter of the cylinder, d= 0.24\ m
  • mass of piston sealing on the top, m_p=15\ kg
  • initial temperature of the piston, T_i=315+273= 588\ K
  • initial height of piston, h_i=0.9\ m
  • atmospheric pressure on the piston, p_a=1 atm=101325\ Pa

(A)

<u>Initial pressure of gas is the pressure balanced by the weight of piston:</u>

P_i=\frac{m_p.g}{\pi.d^2\div 4}

P_i=\frac{15\times 9.8}{\pi\times (0.24^2\div 4)}

P_i=3249.41\ Pa

<em>Which is gauge pressure because it is measured with respect to the atmospheric pressure.</em>

(B)

Given:

  • Final temperature, T_f=18+273=291\ K

<u>Now, volume of air initially in the cylinder:</u>

V_i=\pi.d.h_i

V_i=\pi\times 0.24\times 0.9

V_i=0.6786\ m^3

Using gas law:

\frac{P_i V_i}{T_i}= \frac{P_f V_f}{T_f} ........................................(1)

<em>∵In every condition of equilibrium the gas pressure will be balanced by the weight of the piston so it is an </em><em>isobaric transition</em><em>.</em>

∴P_i=P_f

<u>Hence eq. (1) is reduced to:</u>

\frac{V_i}{T_i}= \frac{V_f}{T_f}

putting respective values:

\frac{0.6786}{588}= \frac{V_f}{291}

V_f=0.3358\ m

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Explain why nuclear fusion takes place only in the center of stars
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