Answer:
v = 7671.57 m/s
T = 1.55 hours
Explanation:
mass of Earth, M = 6 x 10^24 kg
Radius of earth, R = 6400 km = 6.4 x 10^6 m
height, h = 400 km
Velocity is given by

where, G be the universal gravitational constant.
G = 6.657 x 10^-11 Nm^2/kg^2

v = 7671.57 m/s
Let T b the period


T = 5566.53 second
T = 1.55 hours
Answer:
5.92×10⁷ J
Explanation:
We'll begin by converting 15 tons to Newton. This can be obtained as follow:
1 ton = 9806.65 N
Therefore,
15 ton = 15 ton × 9806.65 N / 1 ton
15 ton = 147099.75 N
Next, we shall convert one-quarter (¼) or 0.25 mile to metre. This can be obtained as follow:
100 mi = 160934 m
0.25 mi = 0.25 mi × 160934 / 100 mi
0.25 mi = 402.335 m
Finally, we shall determine the Workdone. This can be obtained as follow:
Force (F) = 147099.75 N
Distance (d) = 402.335 m
Workdone (Wd) =?
Wd = F × d
Wd = 147099.75 × 402.335
Wd = 5.92×10⁷ J
Thus, the Workdone is 5.92×10⁷ J
Answer:
Wg is positive and WT negative.
(Letters in options are all wrongly written).
Explanation:
Remember that the work of a force is the internal product between the force and the displacement
.
Since the displacement is downwards like the weight, the work done by gravity is positive, while the work done by the tension is negative since it points upwards.
Answer:
Explanation:
V₀ = 0 m/s
V = 41 m/s
S = 480 m
___________
a - ?
Distance traveled:
S = (V² - V₀²) / (2*a)
Acceleration :
a = (V² - V₀²) / (2*S)
a = (41² - 0²) / (2*480) = 1.75 m/s²
Answer: x ≈ 36.3 cm
Explanation:
Conservation of momentum during the collision
0.0340(120) + 1.24(0) = (0.0340 + 1.24) v
v = 3.2025 m/s
The kinetic energy of the block/bullet mass will convert to spring potential
½kx² = ½mv²
x = √(mv²/k)
x = √(1.274(3.2025²) / 99.0)
x = 0.363293... ≈ 36.3 cm