Answer:
1.19cm^3 of glycerine
Explanation:
Let Vo= 150cm^3 for both aluminum and glycerine, using expansion formula:
Volume of spill glycerine = change in volume of glycerine - change in volume of aluminum
Volume of glycerine = coefficient of volume expansion of glycerine * Vo* change in temperature - coefficient of volume expansion of Aluminum*Vo* change temperature
coefficient of volume expansion of aluminum = coefficient of linear expansion of aluminum*3 = 23*10^-6 * 3 = 0.69*10^-4 oC^-1
Change in temperature = 41-23 = 18oC
Volume of glycerine that spill = (5.1*10^-4) - (0.69*10^-4) (150*18) = 4.41*10^-4*2700 = 1.19cm3
Answer:
F = (913.14 , 274.87 )
|F| = 953.61 direction 16.71°
Explanation:
To calculate the resultant force you take into account both x and y component of the implied forces:
![\Sigma F_x=480N+513Ncos(32.4\°)=913.14N\\\\\Sigma F_y=513sin(32.4\°)=274.87N](https://tex.z-dn.net/?f=%5CSigma%20F_x%3D480N%2B513Ncos%2832.4%5C%C2%B0%29%3D913.14N%5C%5C%5C%5C%5CSigma%20F_y%3D513sin%2832.4%5C%C2%B0%29%3D274.87N)
Thus, the net force over the body is:
![F=(913.14N)\hat{i}+(274.87N)\hat{j}](https://tex.z-dn.net/?f=F%3D%28913.14N%29%5Chat%7Bi%7D%2B%28274.87N%29%5Chat%7Bj%7D)
Next, you calculate the magnitude of the force:
![F=\sqrt{(913.14N)+(274.87N)^2}=953.61N](https://tex.z-dn.net/?f=F%3D%5Csqrt%7B%28913.14N%29%2B%28274.87N%29%5E2%7D%3D953.61N)
and the direction is:
![\theta=tan^{-1}(\frac{274.14N}{913.14N})=16.71\°](https://tex.z-dn.net/?f=%5Ctheta%3Dtan%5E%7B-1%7D%28%5Cfrac%7B274.14N%7D%7B913.14N%7D%29%3D16.71%5C%C2%B0)
Hi I need help with some questions I have on a quiz / test
Answer: Brittle
Explanation:
took the test and I chose Soft, Soft is the wrong answer don't choose it. The CORRECT ANSWER IS BRITTLE