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True [87]
3 years ago
14

What additional information do you need to prove ∆ABC ≅ ∆DEF by the SAS Postulate?

Physics
1 answer:
Lunna [17]3 years ago
3 0

Answer:

A.) ∠CAB ≅ ∠FDE

Explanation:

The triangle SAS postulate state that two triangles that have congruent side-angle-side are congruent triangles. Take notes that the angle must be in between the two congruent sides. The congruent sides of the first triangle are CA = FD and AB=DE. The angle in between CA and AB is ∠A, while the angle between FD and DE is ∠D.

The angle needed will be:

∠A ≅ ∠D

∠CAB ≅ ∠FDE

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Akimi4 [234]

your answer is the letter (b)


7 0
4 years ago
WAVES AND SOUND
lawyer [7]

Answer:

i think it is B

Explanation:

6 0
3 years ago
Suppose that she pushes on the sphere tangent to its surface with a steady force of F = 75 N and that the pressured water provid
PolarNik [594]

Answer:

The time taken to rotate the sphere one time is,  t = 22 s

Explanation:

Given data,

The mass of the sphere, m = 8200 kg

The radius of the sphere, r = 90 cm

                                             = .9 m

The force applied by the girl, F = 75 N

The moment of inertia of the sphere is,

                            I = 2/5 mr²

                              = (2/5) 8200 x (.9)²

                              = 2657 kg·m²

The torque,

                            τ = I α

                             75 x 0.9 = 2657 x α

                              α = 0.0254 rad/s²

The angular displacement,

                            θ = ½αt²

                             2π =  ½ x 0.0254 rad/s² x t²

                                t = 22 s

Hence, the time taken to rotate the sphere one time is,  t = 22 s

8 0
3 years ago
onsider 1000 mL of a 1.00 × 10-4 M solution of a certain acid HA that has a Ka value equal to 1.00 × 10-4. Water was added or re
solmaris [256]

Answer:

The volume of the final solution, V = 0.0305L

Explanation:

Number of moles = Concentration * volume

Concentration of HA = 1.00 * 10⁻⁴M

Volume of HA = 1000mL = 1 L

Number of moles of HA =  1.00 * 10⁻⁴ * 1

Number of moles of HA =  1.00 * 10⁻⁴ mols

Equation of reaction:

HA → H⁺  +  A⁻

If 1 mol of HA produces 1 mol of H⁺  and  A⁻, 1.00 * 10⁻⁴ mol of HA will produce 1.00 * 10⁻⁴ mol of  H⁺  and  A⁻.

Since only 16% dissociation occurs = 0.16

Number of moles of  H⁺ produced = 0.16 *  1.00 * 10⁻⁴

Number of moles of  H⁺ produced = 1.6 * 10⁻⁵mols

Number of moles of  A⁻ produced = 0.16 *  1.00 * 10⁻⁴

Number of moles of  A⁻ produced = 1.6 * 10⁻⁵mols

Since 16% of HA dissociated into  H⁺  and  A⁻, 84% of HA is left

Number of mols of HA left = 0.84 *  1.00 * 10⁻⁴

Number of mols of HA left =  8.4 * 10⁻⁵mols

Concentration = num of moles/volume

Let the volume of the final solution be V

Conc of HA = 8.4 * 10⁻⁵/V

Conc of H⁺ = 1.6 * 10⁻⁵/V

Conc of A⁻ =  1.6 * 10⁻⁵/V

To calculate the dissociation constant

k_{a} = [H^{+} ][A^{-} ]/[HA]

k_{a}= [1.6 * 10^{-5} /V][1.6 * 10^{-5} /V]/[8.4 * 10^{-5} /V]\\k_{a}= 3.05 * 10^{-6} /V\\k_{a} = 1.00 * 10^{-4}\\ 1.00 * 10^{-4} = 3.05 * 10^{-6} /V\\V= 3.05 * 10^{-6}/ 1.00 * 10^{-4}\\V=3.05 * 10^{-2}\\V=0.0305 L

3 0
3 years ago
Consider a diffraction grating of width 5cm with slits of width 0.0001 cm separated by distance of 0.0002cm 1:what is the corres
sashaice [31]

Answer:

a) d= 0.0002cm

b) m=3

Explanation:

From the question we are told that:

Width of diffraction grating W_g= 5cm

Width of silt w_s 0.0001 cm

Distance d= 0.0002cm

a)

Generally the grafting element is the distance b/w  the silts

d= 0.0002cm

Therefore the grafting element is

d= 0.0002cm

b)

Generally the equation for diffraction state is mathematically given by

 dsin\theta=m\lambda

Since

 sin\theta \leq 1

Therefore

 m \leq \frac{d}{\lambda}

 m \leq \frac{0.0002}{0.000055}

 m \leq 3.6

Therefore orders observed with \lambda is

 m=3

3 0
3 years ago
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