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3 years ago

What additional information do you need to prove ∆ABC ≅ ∆DEF by the SAS Postulate?

Physics

1 answer:

Lunna [17]3 years ago

3 0

Answer:

A.) ∠CAB ≅ ∠FDE

Explanation:

The triangle SAS postulate state that two triangles that have congruent side-angle-side are congruent triangles. Take notes that the angle must be in between the two congruent sides. The congruent sides of the first triangle are CA = FD and AB=DE. The angle in between CA and AB is ∠A, while the angle between FD and DE is ∠D.

The angle needed will be:

∠A ≅ ∠D

∠CAB ≅ ∠FDE

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Mariana [72]

Answer:

142m/s2

Explanation:

The solution is in the attached file below

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3 years ago

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3 years ago

A value with magnitude only is a ?

harkovskaia [24]

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3 years ago

You must exert a force of 5N on a book to slide it across a table.If you do 2.5 J of work in the process, how far has the book m

I am Lyosha [343]

Answer:

0.5 m.

Explanation:

From the question given above, the following data were obtained:

Force (F) = 5 N

Work done (W) = 2.5 J

Distance (s) =?

Workdone is simply defined as the product of force (F) and distance (s) moved in the direction of the force. Mathematically, it is expressed as:

Work done (W) = Force (F) × Distance (s)

W = F × s

With the above formula, we can obtain the distance to which the book has moved as follow:

Force (F) = 5 N

Work done (W) = 2.5 J

Distance (s) =?

W = F × s

2.5 = 5 × s

Divide both side by 5

s = 2.5/5

s = 0.5 m

Therefore, the book moved 0.5 m when the force was applied.

3 0

4 years ago

If a box of supplies is dropped from the cargo hold of an airplane travelling at an altitude of 4,410 meters how long will it ta

Paraphin [41]

Answer:

It will take 30 seconds to reach the ground, and it will be travelling at 294 m/s when it does so. This means that its average velocity was 147 m/s.

Explanation:

$d=v_ot+\dfrac{1}{2}at^2$

Since the initial velocity of a dropped object is 0, we can make this the equation:

$d=\dfrac{1}{2}at^2 \\\\4410=\dfac{1}{2}(9.8)t^2 \\\\t^2=900$

$t=30\text{ seconds}$

The final velocity can be calculated with the formula:

$v_f=v_o+at$

Once again, since there is no initial velocity:

$v_f=at \\\\v_f=(9.8)(30)=294m/s$

Since the initial velocity is 0, the average vertical velocity is 294/2=147 m/s.

Hope this helps!

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3 years ago