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UNO [17]
2 years ago
7

Help needed please!!

Mathematics
1 answer:
Nitella [24]2 years ago
6 0
They r similar shapes so the answer is b
The length is 3
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PLZ HELP ASAP!!! Will give brainlest ❗️❗️❗️❗️
ohaa [14]

Answer:

<em>I</em>(-1,3)

Step-by-step explanation:

Moving 3 units left adds -3 to x value

Moving 6 units up adds 6 to the y value

2 - 3 = -1

-3 + 6 = 3

(-1,3)

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

3 0
3 years ago
Read 2 more answers
X+4y=6<br> 3x+3y=9<br> Answer is 6.3 but how
maksim [4K]

Answer:

X = 2

Y = 1

Step-by-step explanation:

x + 4y = 6

3x + 3y = 9

3x + 12y = 18

3x + 3y = 9

9y = 9

x + 4y = 6

y = 1

x + 4 * 1 = 6

y = 1

x + 4 = 6

y = 1

x = 2

so there ia only 1 solution for this equation is (2;1)

Done :))

8 0
2 years ago
Line / is shown on the graph below. If another line is drawn, perpendicular to line I, what must be its slope?
juin [17]

Answer:

Undefined

Step-by-step explanation:

The slope on the graph is horizontal so there's no slope and the answer is just y = 3

For a line to be perpendicular to a horizontal line, it is going to be a vertical line.

All vertical lines have an undefined slope.

7 0
2 years ago
A proportion often shows the relationship between:
tankabanditka [31]

Answer:

It compares two numbers that can represent many of things. For example, people, food & items.

Step-by-step explanation:

8 0
3 years ago
Let X1 and X2 be two random variables following Binomial distribution Bin(n1,p) and Bin(n2,p), respectively. Assume that X1 and
ryzh [129]

Answer:

a) X1+X2 have distribution Bi(n1+n2, p)

b)

P(X1+X2 = 1 | X2 = 0) =  np(1-p)ⁿ¹⁻¹

P(X1+X2 = 1| X2 = 1) = (1-p)ⁿ¹

P(X1 + X2 = 1) = (1-p)ⁿ¹ * np(1-p)ⁿ²⁻¹+ (1-p)ⁿ²*np(1-p)ⁿ¹-¹

Step-by-step explanation:

Since both variables are independent but they have the same probability parameter, you can interpret that like if the experiment that models each try in both variables is the same. When you sum both random variables toguether, what you obtain as a result is the total amount of success in n1+n2 tries of the same experiment, thus X1+X2 have distribution Bi(n1+n2, p).

b)

Note that, if X2 = k, then X1+X2 = 1 is equivalent to X1 = 1-k. Since X1 and X2 are independent, then P(X1+X2 = 1| X2 = K) = P(X1=1-k|X2=k) = P(X1 = 1-k).

If k = 0, then this probability is equal to P(X1 = 1) = np(1-p)ⁿ¹⁻¹

If k = 1, then it is equal to P(X1 = 0) = (1-p)ⁿ¹

Thus,

P(X1+X2 = 1) = P(X1+X2 = 1| X2 = 1) * P(X2=1) + P(X1+X2 = 1| X2 = 0) * P(X2 = 0) = (1-p)ⁿ¹ * np(1-p)ⁿ²⁻¹+ (1-p)ⁿ²*np(1-p)ⁿ¹-¹

4 0
3 years ago
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