A ball was kicked into the air from a balcony 20 feet above the ground, and the ball's height above the ground, in feet, t seconds after the ball was kicked was h(t) = 20 - 16t2 + 32t. ... Therefore, the maximum height, in feet, of the ball above theground after it was kicked was h(1) = 20 - 16(1)2 + 32(1) = 36.
9514 1404 393
Answer:
A, C, B
Step-by-step explanation:
It is helpful to remember the trig identities ...
sin = 1/csc
cos = 1/sec
tan = 1/cot
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1. sin(θ)cos(θ)sec(θ)csc(θ) = (sin(θ)csc(θ))(cos(θ)sec(θ)) = (1)(1) = 1 . . . matches A
2. 1/cot²(θ)·sec(θ)cos(θ) = 1/(1/tan²(θ))·(1) = tan²(θ) . . . matches C
3. tan(θ)/cot(θ) = tan(θ)/(1/tan(θ)) = tan²(θ) . . . matches B
Answer:
4 option
Step-by-step explanation: because they are 2 zeros so 1 and 2 wont work and theere are 6 2 so 3 wont work so 4 is the answer
Answer:
3675
Step-by-step explanation:
3500x.05 (5%)=175 GCT
3500+175=3675.
$7.40/ 5 pounds
= $1.48/pound
The unit rate is $1.48/pound~
