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Yakvenalex [24]
2 years ago
13

True or False? The graph of sine can be used to construct the graph of the secant function.

Mathematics
1 answer:
amid [387]2 years ago
5 0

True

Note that:

secant \theta = \frac{1}{cos\theta}

The graph of sine and cosine functions are very similar. They only have a shift in the x -axis.

That is,  sin x  =  cos (90  -  x)

Since there is a great similarity between the sine and cosine graphs, and the secant graph is an inverse of the cosine graph, the graph of sine can be used to construct the graph of the secant function

Mathematically:

since  sec x  =  1 / cos x

and, cos x = sin (90 - x)

therefore, sec x = 1 / sin (90 - x)

The graphs of the sine and secant functions are attached to this solution

Learn more here: brainly.com/question/9554579

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A pre-image is dilated by a scale factor of 4. Which statement about the pre-image and its image is true?
nikitadnepr [17]

Answer:(c)

Step-by-step explanation:

8 0
2 years ago
R 3. The mean of 4 numbers is 8. Three of the numbers add up to 22. What is the last number?​
statuscvo [17]
<h2><em><u>Solution</u></em> : </h2>

let the last number be x

we know,

\boxed{mean =  \frac{sum \:  \: of \:  \: all \:  \: observations}{number \:  \: of \:  \: observations} }

So,

\hookrightarrow \: 8 =  \dfrac{22 + x}{4}

\hookrightarrow \: 8 \times 4 = 22 + x

\hookrightarrow \: 32 = 22 + x

\hookrightarrow \: x = 32 - 22

\hookrightarrow \: x = 10

therefore, the last number is 10.

7 0
2 years ago
Which of the following is a trinomial with a constant term?
iVinArrow [24]

Answer:

B

Step-by-step explanation:

because a constant term is a number with out a variable

6 0
2 years ago
14. If the domain of f(x)= x2 +1 is limited to {0,1,2,3), what is the maximum value of the range?
fiasKO [112]

the domain of f(x)= x2 +1 is limited to {0,1,2,3)

the maximum value will be at the maximum value of x which is at x = 3

So, the maximum value of the range will be = 3^2 + 1 = 9 + 1 = 10

7 0
9 months ago
The annual precipitation amounts in a certain mountain range are normally distributed with a mean of 91 inches, and a standard d
Vesna [10]
The sample std. dev. will be (14 inches) / sqrt(49), or (14 inches) / 7, or 2 inches.

Find the z score for 93.8 inches:
       93.8 inches - 91.0 inches          2.8 inches
z = ------------------------------------- = ----------------- = 1.4
                    2 inches                         2 inches

Now find the area under the standard normal curve to the left of z = +1.4.

My calculator returns the following:

normalcdf(-100,1.4) = 0.919.  This is the probability that the mean annual precipitation during those 49 years will be less than 93.8 inches.
 
4 0
3 years ago
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