If sound travels at 5600 m/s through a steel rod,what is the wavelength,given a wave frequency of 2480 Hz

1. Which statement about friction is true?(1 point) A. Static friction and kinetic friction in a system always act in the same d

ArbitrLikvidat [17]

Answer:

true 1Ay 2D

Explanation:

1) In this exercise you are asked to investigate which statements are true

A) True. The friction force opposes the movement caused by the external force,

B) False. Mantuano in the opposite direction force

C) False. The static and scientific friction force act in the same direction, since the second appears when the movement does not start and the static friction decreases.

D) Fale the static and kinetic friction forces act in the same direction

2) How to overcome friction on a ramp

A) False. If the texture of the surface becomes rough, the friction force increases

B) False. Pressing the brick against the surface increases the normal and as the friction is proportional to the normal, it also increases

C) False. By lowering the table the weight component in the friction direction decreases

D) True. When lifting the board, the weight component increases and therefore can become greater than the friction

Wx-fr = ma

W sin tea - my mg cos tea = m a

As it increases, the sine increases and the cosine decreases.

3 0

2 years ago

Superman is standing 393m horizontally away from Lois Lane. A villian drops a rock 4 m directly above Lois. I f Superman is to i

Nat2105 [25]

You have to draw a triangle

5 0

2 years ago

Two wires are perpendicular to each other and form a coordinate axis. The current in the vertical wire is going up (in the posit

sergij07 [2.7K]

Answer:

Magnetic field shall be zero at exactly in between the wires.

Explanation:

We can find the magnetic field by biot Savart law as follows

$\overrightarrow{dB}=\frac{\mu _{0}I}{4\pi }\int \frac{\overrightarrow{dl}\times \widehat{r}}{r^{2}}$

For current carrying wire in positive y direction we have

$\overrightarrow{dB_{1}}=\frac{\mu _{0}Idl}{4\pi }\int \frac{\widehat{j}\times \widehat{r_{1}}}{r_{1}^{2}}$

Similarly for wire carrying current in -y direction we have $\overrightarrow{dB_{2}}=\frac{-\mu _{0}Idl}{4\pi }\int \frac{\widehat{j}\times \widehat{r_{2}}}{r_{2}^{2}}$

Thus the net magnetic field at any point in space is given by

$\overrightarrow{dB_{1}}+\overrightarrow{dB_{2}}$

$\frac{\mu _{0}Idl}{4\pi }\int \frac{\widehat{j}\times \widehat{r_{1}}}{r_{1}^{2}}+\frac{-\mu _{0}Idl}{4\pi }\int \frac{\widehat{j}\times \widehat{r_{2}}}{r_{2}^{2}}=0\\\\\Rightarrow \overrightarrow{r_{1}}=\overrightarrow{r_{2}}$

For points with same position vectors from the 2 wires we have a net zero magnetic field. These points are exactly midway between the 2 wires

4 0

3 years ago

If a star has a large luminosity and also a low surface temperature then it must have:.

Marta_Voda [28]

Answer:

To summarize, the answer is it has a small radius.

Explanation:

This is becuase these characteristics interpert a small radius.

8 0

1 year ago

Question 18(Multiple Choice Worth 2 polnis)

Illusion [34]

Last point, Newton’s first law of motion is the correct answer.

Hope this helps ya

3 0

3 years ago