<h2>Answer </h2>
The kinetic energy is 8100 J.
<u>Explanation</u>
Mass is 50.0kg and velocity is 18 m/s, the kinetic energy is:
As we know the formula of kinetic energy which is K.E = ½ ( mv ^ 2 ),
mass = m = 50.0kg
velocity = v = 18 m / s,
by putting values in the formula,
K.E = ½ ( mv ^ 2 ),
K.E = ½ ( 50kg ) . ( 18 m / s ) ^ 2
K.E = ½ ( 50kg ) . ( 324 ),
=> K.E = 1/2 ( 16200 ),
=> K.E = 16200 / 2,
=> K.E = 8100J.
Hence, the kinetic energy ( K.E ) is 8100 joule ( J ).
Answer:
The average power delivered by the elevator motor during this period is 6.686 kW.
Explanation:
Given;
mass of the elevator, m = 636 kg
initial speed of the elevator, u = 0
time of motion, t = 4.5 s
final speed of the elevator, v = 2.05 m/s
The upward force of the elevator is calculated as;
F = m(a + g)
where;
m is mass of the elevator
a is the constant acceleration of the elevator
g is acceleration due to gravity = 9.8 m/s²
F = (636)(0.456 + 9.8)
F = (636)(10.256)
F = 6522.816 N
The average power delivered by the elevator is calculated as;
Therefore, the average power delivered by the elevator motor during this period is 6.686 kW.
Answer:
<h2>Case i) if
</h2><h2>So initially if the circuit is inductive in nature then its net impedance will decrease after this</h2><h2>Case ii) if
</h2><h2>So initially if the circuit is capacitive in nature then its net impedance will increase after this</h2>
Explanation:
As we know that the impedance of the circuit is given as
when we join another identical capacitor in parallel with previous capacitor in the circuit then we will have for parallel combination
so it is
now we have
Case i) if
So initially if the circuit is inductive in nature then its net impedance will decrease after this
Case ii) if
So initially if the circuit is capacitive in nature then its net impedance will increase after this
Answer:
1) a block going down a slope
2) a) W = ΔU + ΔK + ΔE, b) W = ΔE, c) W = ΔK, d) ΔU = ΔK
Explanation:
In this exercise you are asked to give an example of various types of systems
1) a system where work is transformed into internal energy is a system with friction, for example a block going down a slope in this case work is done during the descent, which is transformed in part kinetic energy, in part power energy and partly internal energy that is represented by an increase in the temperature of the block.
2)
a) rolling a ball uphill
In this case we have an increase in potential energy, if there is a change in speed, the kinetic energy also increases, if the change in speed is zero, there is no change in kinetic energy and there is a change in internal energy due to the stationary rec in the point of contact
W = ΔU + ΔK + ΔE
b) in this system work is transformed into internal energy
W = ΔE
c) There is no friction here, therefore the work is transformed into kinetic energy
W = ΔK
d) if you assume that there is no friction with the air, the potential energy is transformed into kinetic energy
ΔU = ΔK
