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2 years ago

Why is a protective apron or lab coat important to use when working with acids?

Physics

2 answers:

OLga [1]2 years ago

5 0

Answer:

Acids break down fabrics and can cause burns if the acids are strong.

Explanation:

When working with acids, it is advisable for a scientist for wear a protective apron or lab coat because acids break down fabrics and can cause burns.

Acids are chemical substances that produces excess hydroxonium ions in solutions.

Due to their unique properties they are highly corrosive and are used to remove rusts from any surface.
We they come in contact with the human body, they can cause severe burns especially if they are very strong acid.
If an apron is worn, then the body will be shielded.

yanalaym [24]2 years ago

5 0

Answer:

C. Acids break down fabrics and can cause burns if the acids are strong.

Explanation:

i did the quiz on edg

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Alai is comparing the physical property of two materials. He is hitting each with a hammer to observe what happens. What physica

dalvyx [7]

Answer:

C:Hardness

Explanation:

if youre hitting something your going to see wich one breaks first

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1 year ago

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The great astronomer of ancient times who summarized and improved a system of circles upon circles to explain the complicated mo

Ainat [17]

The great astronomer of ancient times who summarized and improved...in a book now called The Almagest) is Ptolemy This is further explained below.

<h3>Who is Ptolemy?</h3>

Generally, Claudius Ptolemy was a Greek mathematician, astronomer, and geographer who lived in the second century CE and is best known for proposing the geocentric model of the cosmos, which was used to explain planetary and stellar movements for the next thousand years.

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1 year ago

the human nervous system can propagate nerve impulses at about 10 squared metered per second. estimate the time it takes to trav

rusak2 [61]

Use the formular d = v x t
d = 2m
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3 years ago

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A 525 kg satellite is in a circular orbit at an altitude of 575 km above the Earth's surface. Because of air friction, the satel

Dafna1 [17]

Answer:

$1.69\cdot 10^{10}J$

Explanation:

The total energy of the satellite when it is still in orbit is given by the formula

$E=-G\frac{mM}{2r}$

where

G is the gravitational constant

m = 525 kg is the mass of the satellite

$M=5.98\cdot 10^{24}kg$ is the Earth's mass

r is the distance of the satellite from the Earth's center, so it is the sum of the Earth's radius and the altitude of the satellite:

$r=R+h=6370 km +575 km=6945 km=6.95\cdot 10^6 m$

So the initial total energy is

$E_i=-(6.67\cdot 10^{-11})\frac{(525 kg)(5.98\cdot 10^{24} kg)}{2(6.95\cdot 10^6 m)}=-1.51\cdot 10^{10}J$

When the satellite hits the ground, it is now on Earth's surface, so

$r=R=6370 km=6.37\cdot 10^6 m$

so its gravitational potential energy is

$U = -G\frac{mM}{r}=-(6.67\cdot 10^{-11})\frac{(525 kg)(5.98\cdot 10^{24}kg)}{6.37\cdot 10^6 m}=-3.29\cdot 10^{10} J$

And since it hits the ground with speed

$v=1.90 km/s = 1900 m/s$

it also has kinetic energy:

$K=\frac{1}{2}mv^2=\frac{1}{2}(525 kg)(1900 m/s)^2=9.48\cdot 10^8 J$

So the total energy when the satellite hits the ground is

$E_f = U+K=-3.29\cdot 10^{10}J+9.48\cdot 10^8 J=-3.20\cdot 10^{10} J$

So the energy transformed into internal energy due to air friction is the difference between the total initial energy and the total final energy of the satellite:

$\Delta E=E_i-E_f=-1.51\cdot 10^{10} J-(-3.20\cdot 10^{10} J)=1.69\cdot 10^{10}J$

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2 years ago

I need to speak with zuka

Alex787 [66]

Answer:

DMs are not accessible anymore. I assume Zuka is a staff member? the only way to talk to a staff member anymore is to report something, but even then, the probably won't even look at what they're deleting :/

May I have brainliest please? :)

3 0

2 years ago