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Stells [14]
2 years ago
13

Divide 4 ÷ 2 /5 = If you don’t answer-

Mathematics
2 answers:
Vitek1552 [10]2 years ago
7 0

Answer:

0.1

Step-by-step explanation:

Dmitriy789 [7]2 years ago
6 0
I think the answer is 10
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A students home is 3.25 miles from school. A soda shop is located 900 feet farther down the road from school. What is the total
notka56 [123]

1 mile = 5,280 feet.

Convert the 0.25 mile to feet:

0.25 miles = 0.25 x 5,280 = 1,320 feet.

Add the soda shop distance to this:

1,320 + 900 = 2,220 feet.


Total distance is 3 miles and 2,220 feet


5 0
3 years ago
What is the image of (9,3) after a dilation by a scale factor of 3 centered at the<br> origin?
sergiy2304 [10]

Answer:  (27, 9)

Multiply the original coordinates by the scale factor 3 to get this answer

9*3 = 27

3*3 = 9

This only works if the center of dilation is the origin.

The general rule is (x,y) \to (kx, ky) where k is the scale factor.

7 0
3 years ago
C=27+10h where c= cost in dollars and h= number of hours rented ​
gavmur [86]

Answer:

that help

Step-by-step explanation:

10h+27+−27=c+−27

10h=c−27

10h10=c−2710

h=110c+−2710

Answer:

h=110c+−2710

3 0
3 years ago
After solving the equation x^2+ 9 = 6x, Donna stated that the Fundamental Theorem of Algebra is true for this equation. However,
Georgia [21]

Answer:

Step-by-step explanation:

The Fundamental Theorem of Algebra states that the number of complex roots a polyomial has is equal to its highest exponent.  This is a squared polynomial; second degree; quadratic.  When it is factored, no matter what types of numbers you get as the solution, you will ALWAYS have 2 of them.  When this quadratic is factored, we get that x = 3 and x = 3.  That means that this is a quadratic that touches the x-axis at (3, 0).  It doesn't go through, it only touches.  We do have 2 roots, but since they're the same, we say we have a multiplicity 2 of that root.  The closest you'll come to that in your choices is A.  Apparently your text refers to multiplicity 2 as a double root.

3 0
3 years ago
Problem 1: 2x &gt; 4x - 6<br> problem 2: -3r &lt; 10 - r<br> problem 3: 5c - 4 &gt; 8c + 2
Trava [24]
<span>Problem 1: 2x > 4x - 6
                  2x < 6  
                    x < 3

problem 2: -3r < 10 - r
                   -2r < 10
                      r > -5

problem 3: 5c - 4 > 8c + 2
                       3c < -6
                         c < -2</span>
8 0
3 years ago
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