Question

A chemist prepares a solution of aluminum sulfite by measuring out 109 umol of aluminum sulfite into a 350 mL volumetric flask and filling the flask to the mark with water.
Calculate the concentration in mmol/L of the chemist's aluminum sulfite solution. Be sure your answer has the correct number of significant digits.

Answer 1

Answer:

0.311 mmol/L

Explanation:

109  μmol = 109*10^(-6) mol

109*10^(-6) mol = 109*10^(-6) mol*(10^3 mmol/1mol) = 109*10^(-3) mmol =

=0.109 mmol

350 mL = 0.350 L

0.109 mmol/0.350 L = 0.311 mmol/L