Answer:
entropy increases when a glass of water is set in the sun until the water evaporates.
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Answer:
(a) 0.699 kJ/K
(b) -0.671 kJ/K
(c) 0.028 kJ/K
Explanation:
The Refrigerant-134a flows into the evaporator as a saturated liquid-vapor mixture and flows out as a saturated vapor at a saturation pressure of 160 kPa and temperature of -15.64°C (estimated from the Saturated Refrigerant-134a Temperature Table).
(a) The entropy change of the refrigerant (ΔS
) = Q/T
Q = 180 kJ
T = -15.64 + 273.15 = 257.51 K
ΔS = Q/T = 180/257.51 = 0.699 kJ/K
(b) The entropy change (ΔS
) of the cooled space (ΔS) = -Q/T
Q = -180 kJ
T = -5 + 273.15 = 268.15 K
ΔS = Q/T = -180/268.15 = -0.671 kJ/K
(c) The total entropy change for this process (ΔS
) = ΔS + ΔS = 0.699 - 0.671 = 0.028 kJ/K
Answer:
why cant you just say the grasshopper eats the marsh grass the shrew eats the grasshopper and the hawk eats the shrew.
Explanation:
this makes sense to me but im not sure.
Answer:
a. Solar
Explanation:
Solar energy causes water to evaporate, which is the driving force of the water cycle. Water from the ocean evaporates and comes back down as rain and it gives life to the Earth and so it continues.
The estimated population of the sea turtles for that location is 160 turtles
Let b represent the total turtles in the location.
<h3>Data obtained from the question</h3>
- Captured marked turtle = 15
The estimated turtles in sea can be obtained as follow:
Mark in sea / Total in sea = captured marked turtle / Captured turtle
40 / b = 15 / 60
Cross multiply
b × 15 = 40 × 60
b × 15 = 2400
Divide both side by 15
b = 2400 / 15
b = 160 turtles
Thus, the estimated turtles in the sea is 160 turtles
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