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Art [367]
3 years ago
9

Rewrite the equation in slope-intercept form 5x - 6y = 12

Mathematics
1 answer:
inessss [21]3 years ago
8 0

Answer:

M = \frac{5}{6} Is correct answer

Step-by-step explanation:

Write in slope-intercept form,  y = m x + b.

m = \frac{5}{6}

Graph in pic

(Hope this helps can I pls have brainlist (crown)☺️

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5x-3=19? Answer for Brainliest
vampirchik [111]

Answer:

x = 4.4

Step-by-step explanation:

I'm going to assume you want to solve for x so here we go.

You need to work backwards for this equation, and whatever you do to the LHS, you do to the RHS.

First, you need to remove the minus 3, which means that on both sides, you add 3. Adding three on the LHS makes the -3 disappear, and adding 3 on the RHS makes the 19 go to a 22.

Your equation is now 5x=22.

Since 5x means 5 × x, to get rid of it, you need to divide 5x by 5. Doing it to the LHS will make the five disappear, and doing it to the RHS will make it go to 22 ÷ 5 which equals 4.4

Therefore, x = 4.4

4 0
3 years ago
Find an equation of the plane that contains the points p(5,−1,1),q(9,1,5),and r(8,−6,0)p(5,−1,1),q(9,1,5),and r(8,−6,0).
topjm [15]
Given plane passes through:
p(5,-1,1), q(9,1,5), r(8,-6,0)

We need to find a plane that is parallel to the plane through all three points, we form the vectors of any two sides of the triangle pqr:
pq=p-q=<5-9,-1-1,1-5>=<-4,-2,-4>
pr=p-r=<5-8,-1-6,1-0>=<-3,5,1>

The vector product pq x pr gives a vector perpendicular to both pq and pr.  This vector is the normal vector of a plane passing through all three points
pq x pr
=
  i   j   k
-4 -2 -4
-3  5  1
=<-2+20,12+4,-20-6>
=<18,16,-26>

Since the length of the normal vector does not change the direction, we simplify the normal vector as
N = <9,8,-13>

The required plane must pass through all three points.
We know that the normal vector is perpendicular to the plane through the three points, so we just need to make sure the plane passes through one of the three points, say q(9,1,5).

The equation of the required plane is therefore
Π :  9(x-9)+8(y-1)-13(z-5)=0
expand and simplify, we get the equation
Π  :  9x+8y-13z=24

Check to see that the plane passes through all three points:
at p: 9(5)+8(-1)-13(1)=45-8-13=24
at q: 9(9)+8(1)-13(5)=81+9-65=24
at r: 9(8)+8(-6)-13(0)=72-48-0=24
So plane passes through all three points, as required.

3 0
3 years ago
PLEASE HELP
Law Incorporation [45]
None of these are correct, however of the ones you listed, A would be the most likely to be correct. y is greater than 3... therefore making y a number greater than zero.
6 0
3 years ago
Use the formula to evaluate the series 1/4 + 1/9 + 1/27 + 1/81.
Dmitriy789 [7]
Is the first term supposed to be 1/4, or did you actually mean 1/3?

I'll assume the latter. Write

S=\dfrac13+\dfrac19+\dfrac1{27}+\dfrac1{81}
S=\dfrac13+\dfrac1{3^2}+\dfrac1{3^3}+\dfrac1{3^4}
\dfrac13S=\dfrac1{3^2}+\dfrac1{3^3}+\dfrac1{3^4}+\dfrac1{3^5}
\implies S-\dfrac13S=\dfrac13-\dfrac1{3^5}
\dfrac23S=\dfrac13\left(1-\dfrac1{3^4}\right)
S=\dfrac12\left(1-\dfrac1{81}\right)
S=\dfrac{40}{81}
8 0
3 years ago
190 + 200 its IMPOSSIBLE
nirvana33 [79]

Answer: 390

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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