Moles of Carbondioxide-CO₂ produced = 20 moles
<h3>Further explanation</h3>
The combustion of hydrocarbons with excess oxygen will produce carbon dioxide and water(CO₂+H₂O), whereas if there is not much oxygen, carbon monoxide and water(CO+H₂O) will be obtained.
The reaction coefficient in a chemical equation shows the mole ratio of the reacting compounds
Reaction (combustion of butane) :
<em>2C₄H₁₀+13O₂⇒8CO₂+10H₂O</em>
Butane reacts completely, then Butane is the limiting reactant and oxygen as the excess reactant, so the moles of Carbon dioxide are based on the butane moles as the limiting reactant.
moles of butane - C₄H₁₀ = 5 moles
From the reaction, the mol ratio of C₄H₁₀ and CO₂ : 2 : 8, so mol CO₂ :
Answer:
3. doubles
Explanation:
for an ideal gas behavior, the relationship between volume and temperature is given by Charles law
Charles law states that the volume of a given mass of gas is directly proportional to its temperature provided that pressure remains constant. Mathematically, this is represented as
V ∝ T
V=KT
K = V/T
where V is the volume of the gas
T is the Temperature
k represents the constant of proportionality
For initial and final conditions of a gas,
= 
where 1 and 2 represent initial and final conditions respectively
therefore, T₁ = 100 and T₂ = 200
= 
200 × V₁ = 100 × V₂
divide both sides by 100
2V₁ = V₂
final volume,V₂ = 2V₁
there the volume doubles
Answer:
carbon molecules share their 4 valence electrons through single, double, and triple bonds.
Explanation:
I think you meant ionic bonds not lonic bonds
Answer:
31.345 cm³
Explanation:
Given:
Mass of the empty flask, m = 56.12 g
Mass of the flask filled with water, M = 87.39 g
Density of the water, ρ = 0.9976 g/cm³
now,
the mass of water filled in the flask, Mw = M - m = 87.39 - 56.12 = 31.27 g
also,
Density = mass / volume
thus, for water
0.9976 = 31.27 / volume
or
volume of water = 31.345 cm³
hence, the volume of flask is the volume of water filled = 31.345 cm³
