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dezoksy [38]
3 years ago
15

Which best describes the purpose of a controlled experiment?

Chemistry
1 answer:
Kazeer [188]3 years ago
4 0
Not 100% sure but i would say to prevent an undesired change in a variable
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What are some facts about beryllium?
Triss [41]
It is a hard metal but is brittle at room temperature
5 0
4 years ago
Mercury has a density of <br> 13.55 g/mL .What would be the volume of a 122 g sample?
Salsk061 [2.6K]

Answer:

V = 9.0037

Explanation:

V = M/D

V = 122/13.55

V = 9.0037

4 0
3 years ago
Elabore el balance de la ecuación por oxido reducción enumerando cada paso
Rasek [7]

Answer:

{ \rm{5CaC _{2}O _{4(aq)}+ 2KMnO _{4(aq)} + 8H _{2} SO _{4(aq)}  → 5CaSO _{4(s)}+ 2Mn SO _{4(aq)}+ K _{2} SO _{4(s)} + 10CO _{2(g)}  + 8H _{2} O _{l} }}

Explanation:

This is a redox reaction formed by combining two half equations.

Check the image above, sorry if my handwriting is poor :(

8 0
3 years ago
What marine province contains deep ocean trenches that form along convergent plate boundaries as a result of subduction?
ira [324]

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A.Mid ocean ridge i think

Explanation:

3 0
4 years ago
A 10 pound block of lead-210 has a half-life of 22 years. What percentage of the block still contains lead-210 after 60 years?
avanturin [10]

Answer:

The percentage of the block contains 15% after 60 years.

Explanation:

Step 1: Formula for half-life time

To calculate the half-life time we will use the following formula:

At = A0 * 1/2 ^(x/t)

With At = the quantity after a time t

A0 = The quantity at time t = 0 (start)

x = time in this case = 60 years

t= half-life time = 22 years

Step 2: Calculate the percentage after 60 years

In this case: after 60 years the percentage will be

A0= 10 * 1/2 ^(60/22)

A0 = 1.5

A0 / At  = 1.5 /10 = 0.15

0.15 *100% = 15 %

The percentage of the block contains 15% after 60 years.

7 0
3 years ago
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