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gavmur [86]
3 years ago
13

A 10 pound block of lead-210 has a half-life of 22 years. What percentage of the block still contains lead-210 after 60 years?

Chemistry
1 answer:
avanturin [10]3 years ago
7 0

Answer:

The percentage of the block contains 15% after 60 years.

Explanation:

Step 1: Formula for half-life time

To calculate the half-life time we will use the following formula:

At = A0 * 1/2 ^(x/t)

With At = the quantity after a time t

A0 = The quantity at time t = 0 (start)

x = time in this case = 60 years

t= half-life time = 22 years

Step 2: Calculate the percentage after 60 years

In this case: after 60 years the percentage will be

A0= 10 * 1/2 ^(60/22)

A0 = 1.5

A0 / At  = 1.5 /10 = 0.15

0.15 *100% = 15 %

The percentage of the block contains 15% after 60 years.

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The graph above shows the distribution of molecular speeds for four different gases at the same temperature. What property of th
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Answer:

The correct option is;

D.) The molecular masses of the gases, because the gas molecules have the same average kinetic energy and mass can be calculated using the equation, KE_{avg} = \dfrac{1}{2}  \times m \times v^2

Explanation:

The graph shows the proportion of the atoms of each gas have a given velocity

The given parameters of the graphs are;

The dependent variable of the graph = The number of molecules

The independent variable =  The molecular speed (m/s)

The temperature of the gases = The same temperature

v_{rms} = \sqrt{\dfrac{3 \cdot R \cdot T}{MW} }

Therefore, from the above equation, at constant temperature, the root mean square velocity varies inversely as the molecular weight

Similarly from the kinetic energy equation, we have;

KE_{avg} = \dfrac{1}{2}  \times m \times v^2

Whereby, the energy contained in each of the four gas are the same, we have;

For increasing molecular mass by a factor of 2, the velocity decreases by a factor of 4.

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3 years ago
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A mouse has 20 chromosomes. If one of its cells goes through mitosis, how many cells would be present after mitosis?
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Answer:

22

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Which two trials could be used to measure the surface area
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3 years ago
1. Which of the following correctly represents a balance chemical equation? (a) NaCl + 2H2O → 2NaOH + 2Cl2 + H2 (b) 2NaCl+H2O →
butalik [34]

Answer:

thx sa points

Explanation:

8 0
2 years ago
15 POINTS PLEASE HELP What volume of water must be added to 35mL of 2.6m KCl to reduce its concentration to 1.2m? Please explain
BartSMP [9]
First, find the volume the solution needs to be diluted to in order to have the desired molarity:
You have to use the equation M₁V₁=M₂V₂ when ever dealing with dilutions.

M₁=the starting concentration of the solution (in this case 2.6M)
V₁=the starting volume of the solution (in this case 0.035L)
M₂=the concentration we want to dilute to (in this case 1.2M)
V₂=the volume of solution needed for the dilution (not given)

Explaining the reasoning behind the above equation:
MV=moles of solute (in this case KCl) because molarity is the moles of solute per Liter of solution so by multiplying the molarity by the volume you are left with the moles of solute.  The moles of solute is a constant since by adding solvent (in this case water) the amount of solute does not change.  That means that M₁V₁=moles of solute=M₂V₂ and that relationship will always be true in any dilution.

Solving for the above equation:
V₂=M₁V₁/M₂
V₂=(2.6M×0.035L)/1.2M
V₂=0.0758 L
That means that the solution needs to be diluted to 75.8mL to have a final concentration of 1.2M.

 Second, Finding the amount of water needed to be added:
Since we know that the volume of the solution was originally 35mL and needed to be diluted to 75.8mL to reach the desired molarity, to find the amount of solvent needed to be added all you do is V₂-V₁ since the difference in the starting volume and final volume is equal to the volume of solvent added.
75.8mL-35mL=40.8mL
40.8mL of water needs to be added

I hope this helps.  Let me know if anything is unclear.
Good luck on your quiz!
5 0
4 years ago
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