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BabaBlast [244]
2 years ago
10

Mercury has a density of 13.55 g/mL .What would be the volume of a 122 g sample?

Chemistry
1 answer:
Salsk061 [2.6K]2 years ago
4 0

Answer:

V = 9.0037

Explanation:

V = M/D

V = 122/13.55

V = 9.0037

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Equal molar quantities of Ca2 and EDTA (H4Y) are added to make a 0.010 M solution of CaY2- at pH 10. The formation constant for
abruzzese [7]

Answer:

the concentration of free Ca2⁺ in this solution is 7.559 × 10⁻⁷

Explanation:

Given the data in the question;

Ca^{2+ + y^{4- ⇄  CaY^{2-

Formation constant Kf

Kf = CaY^{2- / ( [Ca^{2+][y^{4-] ) = 5.0 × 10¹⁰

Now,

[y^{4-] = \alpha _4CH_4Y; ∝₄ = 0.35

so the equilibrium is;

Ca^{2+ + H_4Y ⇄  CaY^{2- + 4H⁺

Given that; CH_4Y = Ca^{2+     { 1 mol Ca^{2+  reacts with 1 mol H_4Y  }

so at equilibrium, CH_4Y = Ca^{2+ = x

∴

Ca^{2+ + y^{4- ⇄  CaY^{2-

x        + x         0.010-x

since Kf is high, them x will be small so, 0.010-x is approximately 0.010

so;

Kf = CaY^{2- / ( [Ca^{2+][y^{4-] ) =  CaY^{2- / ( [Ca^{2+][\alpha _4CH_4Y] )  = 5.0 × 10¹⁰

⇒ CaY^{2- / ( [Ca^{2+][\alpha _4CH_4Y] )  = 5.0 × 10¹⁰

⇒ 0.010 / ( [x][ 0.35 × x] )  = 5.0 × 10¹⁰

⇒ 0.010 / 0.35x²  = 5.0 × 10¹⁰

⇒ x² = 0.010 / ( 0.35 × 5.0 × 10¹⁰ )

⇒ x² = 0.010 / 1.75 × 10¹⁰

⇒ x² = 0.010 / 1.75 × 10¹⁰

⇒ x² = 5.7142857 × 10⁻¹³

⇒ x = √(5.7142857 × 10⁻¹³)

⇒ x = 7.559 × 10⁻⁷

Therefore, the concentration of free Ca2⁺ in this solution is 7.559 × 10⁻⁷

8 0
2 years ago
In many of the steps in the lab, a mixture was centrifuged and then decanted. In general terms, what is accomplished by these st
nirvana33 [79]

Answer:

to separate the compounds by gravity

Explanation:

Centrifuging is the process of separating compound in a liquid mixture by means of gravity and settling. This makes use of the density principle. In the process, the sample is added to the centrifuge. This is then rotated at a certain speed, say 50 rpm. The circular motion creates a force of gravity that pulls the compounds downwards. This then separate the compounds. The heaviest and most dense go down first, then the lighter particles on the top.  

3 0
3 years ago
How many litres of 15% (mass/ volume) copper sulphate solution
givi [52]
Take 15/100 X 75 = The answer
4 0
3 years ago
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The actual yield of a product in a reaction was measured as 4.20 g. If the theoretical yield of the product for the reaction is
Dmitry_Shevchenko [17]

Answer:

3

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3 0
2 years ago
How much work (in J) is involved in a chemical reaction if the volume decreases from 5.00 to 1.48 L against a constant pressure
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Given:
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p = 0.818 atm = 0.819*101325 Pa = 82985.2 Pa

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Answer: 292.1 J
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3 years ago
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