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3 years ago

Explain how nuclear waste is contained, stored, and disposed of, and how each method affects the environment

Chemistry

1 answer:

Nonamiya [84]3 years ago

4 0

Explain how nuclear waste is contained, stored, and disposed of, and how each method affects the
environment

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You start with 1 L of CO2 at standard temperature and pressure in a closed container. If you raise the temperature of the gas, t

pychu [463]

Answer:

Increase

Explanation:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

If the initial temperature and pressure is standard,

Pressure = 1 atm

Temperature = 273.15 K

then we increase the temperature to 400.0 K, The pressure will be,

1 atm / 273.15 K = P₂/400.0K

P₂ = 1 atm × 400.0 K / 273.15 K

P₂ = 400.0 atm. K /273.15 K

P₂ = 1.46 atm

Pressure is also increase from 1 atm to 1.46 atm.

8 0

3 years ago

Write a variable expression that represents the following word phrase: three more than two times the difference of x and one.

Inga [223]

Convert the wordphrase to expression

$\\ \rm\longmapsto 2(x-1)+3$

$\\ \rm\longmapsto 2x-2+3$

$\\ \rm\longmapsto 2x+1$

5 0

3 years ago

Read 2 more answers

How many significant figures in 11 soccer players

maria [59]

Counting gives an exact number and exact numbers have infinite sig figs.

3 0

4 years ago

Nitric acid with a concentration of 1mol/dm has a pH

goldenfox [79]

Water is neutral with ph 7. when we add water to acidic solution, it will be less acidic. so the pH of acid increases

6 0

3 years ago

3. What mass of copper could be deposited from a copper(II) Sulphate solution using a current of 5.0 A over 100 seconds? ( F =96

arsen [322]

Mass of copper : 0.165 g

<h3>Further explanation</h3>

Given

5.0 A over 100 seconds

Required

Mass of copper

Solution

Faraday's law:

<em>The mass of the substance formed at each electrode is proportional to the electric current flowing in the electrolysis</em>

<em /> $\tt W=\dfrac{e.i.t}{96500}$ <em />

e = Ar / valence = eqivalent weight

i = current

t = time

W = weight

CuSO₄ ----> Cu²⁺ + SO₄²⁻

Cu ----> Cu²⁺ + 2e

e = Ar/2

= 63,5/2 = 31,75

$\tt W=\dfrac{31.75\times 5\times 100}{96500}=0.165~g$

8 0

3 years ago