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3 years ago

what type of recording do you think would be the best method of submitting evidence to a crime lab? why?

Chemistry

2 answers:

Blababa [14]3 years ago

6 0

Answer:

The type of recording that is the best and most useful method of submitting evidence to a crime lab is by videography.

The videography is the type of evidence that pretty much contains everything that can be get from a recording because it has both the visual aspects and the audio aspects of the crime scene. It can be said that the videography represents the ultimate type of notes.

Explanation:

Margaret [11]3 years ago

4 0

The type of recording that is the best and most useful method of submitting evidence to a crime lab is by videography.

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Can anyone answer this?? Thanks in advance AlCl3 + Cu = ?

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Reaction won't occur
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3 years ago

Ptrpared a solution of sodium chloride (NaCl) by measuring out 49.Umol of sodium chloride into 150. ML. Volumetric flask and fil

ArbitrLikvidat [17]

Answer:

The answer to your question is below

Explanation:

Data

Substance = NaCl

moles of NaCl = 49

volume = 150 ml

Process

Molarity is a unit of concentration that makes a relation of the moles of a substance and the volume.

Molarity = moles / volume (L)

1.- Convert 150 ml to L

1000 ml ------------------ 1 L

150 ml ----------------- x

x = (150 x 1) / 1000

x = 0.15 L

2.- Substitution

Molarity = 49 / 0.15

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I have a doubt if the number of moles is 49 moles or 49μmoles

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3 years ago

How many valence electrons configuration of oxygen?

Ganezh [65]

Oxygen had 6 valence electrons

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3 years ago

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3 years ago

A sample containing 2.30 mol of Ne gas has an initial volume of 8.00 L. What is the final volume, in liters, when the following

marta [7]

Answer:

a. 4,00L

b. 16,00L

c. 12,31L

Explanation:

Avogadro's law says:

$\frac{V_1}{n_1} =\frac{V_2}{n_2}$

a. If initial conditions are 2,30mol and 8,00L and you lose one-half of atoms, that means you have 1,15mol:

$\frac{8,00L}{2,30mol} =\frac{V_2}{1,15mol}$

V₂ = 4,00L

b. If initial conditions are 2,30mol and 8,00L and you add 2,30mol, that means you have 4,60mol:

$\frac{8,00L}{2,30mol} =\frac{V_2}{4,60mol}$

V₂ = 16,00L

c. 25,0g of Ne are:

25,0g × (1mol / 20,1797g) = 1,24 moles of Ne. That means you have 2,30mol - 1,24mol = 3,54mol of Ne

$\frac{8,00L}{2,30mol} =\frac{V_2}{3,54mol}$

V₂ = 12,31L

I hope it helps!

6 0

3 years ago