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bazaltina [42]
3 years ago
15

Separate the pennies you have into two groups: one group with pennies dated before 1982 and the other with pennies dated after 1

982. Compare the two groups. Record any similarities or differences in size or appearance that you notice between the two groups.
Chemistry
1 answer:
Marat540 [252]3 years ago
8 0

Answer:

Srry i don't know about it so...

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Heterozygous- a person having two different alleles for a gene is also called
Lisa [10]

Answer:

heterozygous.

Explanation:

A genotype consisting of two different alleles of a gene for a particular trait (Aa). Individuals who are heterozygous for a trait are referred to as heterozygotes.

3 0
3 years ago
pplication)Using multiple models simultaneously: This FNT refers to a processinvolving three moles of a diatomic gas (which beha
Fiesta28 [93]

Complete Question

Questions Diagram is attached below

Answer:

*  W=1142.86Joule

*  Q=997.7J

*  H=2140.5J

Explanation:

From the question we are told that:

Temperature T=337K

Pressure P=(60-55)Pa*10^5

VolumeV=(1.6-1.4)m^3*10^{-3}

Generally the equation for gas Constant is mathematically given by

\frac{P_2}{P_1}=\frac{V_1}{V_2}^n

 \frac{55*10^5}{60*10^5}=\frac{1.4*10^{-3}}{1.6*10^{-3}}^n

 n=0.65

Therefore

Work-done

 W=\int{pdv}

 W=\frac{55*10^5*1.6*10^{-3}*60*10^5*1.4*10^{-3}}{1-0.65}

 W=1142.86Joule

Generally the equation for internal energy is mathematically given by

 Q=mC_vdT\\\\Q=\frac{3*1*3.314*16}{1.4-1}

 Q=997.7J

Therefore

 H=Q+W

 H=997.7J-11.42.9

 H=2140.5J

5 0
3 years ago
How many moles are there in 7.5 L Of H2
True [87]
So multiply number of moles x number of atoms/mole = 1.8066 x 10^24 atoms of H2. One mole of any gas at STP has a volume of 22.4 L. So first determine the number of moles of gas you have.
for example do 7
7.5 \div 22.4
that 's what I think
3 0
3 years ago
Identify the oxidizing agent and the reducing agent for 4Li(s) + O_2 (g) to 2Li_2O(s).
wolverine [178]

Answer: Li is the reducing agentg and O is the oxidizing agent.

Explanation:

1) The oxidizing agent is the one that is reduced and the reducing agent is the one that is oxidized.

2) The given reaction is:

4Li(s) + O₂ (g) → 2 Li₂O(s)

3) Determine the oxidation states of each atom:

Li(s): oxidation state = 0 (since it is alone)

O₂ (g): oxidation state = 0 (since it is alone)

Li in Li₂O (s) +1

O in Li₂O -2

That because 2× (+1) - 2 = 0.

4) Determine the changes:

Li went from 0 to + 1, therefore it got oxidized and it is the reducing agent.

O went from 0 to - 2, therefore it got reduced and it is the oxidizing agent.

7 0
4 years ago
Read 2 more answers
You have 150. g of a bleach solution. The percent by mass of the solute, sodium hypochlorite (NaOCI), is 3.62%.
Taya2010 [7]

Answer:

There are 5.43 grams of NaOCl

Explanation:

The given percent by mass of the solute tells us that out of the 150 g of the solution, 3.62% are due solely to the solute.

In other words, <u>the mass of the solute in the solution is</u>:

  • 150 g * 3.62/100 = 5.43 g

Thus, in 150 grams of the given bleach solution, there are 5.43 grams of sodium hypochlorite.

4 0
3 years ago
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