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Maksim231197 [3]
3 years ago
8

Find the coefficient of fourth term of (-x -3)^5

Mathematics
1 answer:
vodomira [7]3 years ago
4 0

Answer:

-270

Step-by-step explanation:

Here, we want to know the coefficient of the fourth term.

The coefficients according to pascal triangle for the expansion is 1 5 10 10 5 1

So the expansion looks as follows;

1[(-x)^5(-3)^0] + 5[(-x)^4(-3)^1)] + 10[(-x)^3(-3)^2) + 10[(-x)^2(-3)^3] + ...........

So the fourth term we are dealing with is

10[(-x)^2(-3)^3)]

So the value here is

10 * x^2 * -27

= -270 x^2

So the coefficient is -270

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Step-by-step explanation:

To solve:

5x² − 3x + 17 = 9

or

⇒ 5x² − 3x + 17 - 9 = 0

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⇒ 5x² − 3x + 8 = 0

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the roots of the equation in the form ax² + bx + c = 0 is given as:

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Hence,

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and there are no real roots of the equation given above

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